\(M=\frac{2^{13}.3^7}{2^{15}.3^2.9^2}\)
K
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DP
1
13 tháng 9 2015
\(\frac{2^{13}.3^7}{2^{15}.3^2.9^2}=\frac{2^{13}.3^7}{2^{15}.3^6}=\frac{3}{4}\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.3^8}{3^6.2^{15}}=3^2=9\)
F
1
DK
10 tháng 6 2017
a, \(\frac{2^{30}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}=\frac{2^{13}.\left(2^{17}.5^7+5^{27}\right)}{2^{10}.\left(2^{17}.5^7+5^{27}\right)}=\frac{2^{13}}{2^{10}}=2^3=8\).
b, \(\frac{81.2^2+3^4+20.9^2}{16.3^2+45+2^2.9}=\frac{3^4.2^2+3^4+20.3^4}{16.3^2+3^2.5+2^2.3^2}=\frac{3^4.\left(2^2+1+20\right)}{3^2.\left(16+5+2^2\right)}=\frac{3^4.25}{3^2.25}=\frac{3^4}{3^2}=3^2=9\)
DH
1
12 tháng 5 2022
2: \(=\dfrac{0.8}{\dfrac{16}{25}-\dfrac{1}{25}}+\dfrac{\dfrac{71}{75}\cdot\dfrac{7}{4}}{\dfrac{119}{36}\cdot\dfrac{36}{17}}\)
\(=\dfrac{4}{5}\cdot\dfrac{5}{3}+\dfrac{71}{300}=\dfrac{471}{300}=\dfrac{157}{100}\)
3: \(=\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{2}{6}-\dfrac{2}{8}+\dfrac{2}{10}}{\dfrac{7}{6}-\dfrac{7}{8}+\dfrac{7}{10}}\)
=2/7-2/7=0
\(M=\frac{2^{13}.3^7}{2^{15}.3^2.9^2}=\frac{2^{13}.3^7}{2^{13}.2^2.3^2.\left(3.3\right)^2}=\frac{2^{13}.3^7}{2^{13}.2^2.3^8}=\frac{1}{4.3}=\frac{1}{12}\)