1.Tính a) \(\frac{6}{5}+\frac{6}{35}-\frac{6}{125}-\frac{6}{2009}-\frac{6}{2011}\) ______________________________________ \(\frac{7}{5}+\frac{7}{35}+\frac{7}{125}+\frac{7}{2009}+\frac{7}{2011}\)b) \(\left(1-\frac{1}{2^2}\right).\left(1-\frac{1}{3^2}\right).\left(1-\frac{1}{4^2}\right)....\left(1-\frac{1}{1998^2}\right)\)giúp mình với.Cảm ơn trước...
Đọc tiếp
1.Tính
a) \(\frac{6}{5}+\frac{6}{35}-\frac{6}{125}-\frac{6}{2009}-\frac{6}{2011}\)
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\(\frac{7}{5}+\frac{7}{35}+\frac{7}{125}+\frac{7}{2009}+\frac{7}{2011}\)
b) \(\left(1-\frac{1}{2^2}\right).\left(1-\frac{1}{3^2}\right).\left(1-\frac{1}{4^2}\right)....\left(1-\frac{1}{1998^2}\right)\)
giúp mình với.Cảm ơn trước nha
a)
\(\frac{-\frac{6}{5}-\frac{6}{35}-\frac{6}{125}-\frac{6}{2009}-\frac{6}{2011}}{\frac{7}{5}+\frac{7}{35}+\frac{7}{125}+\frac{7}{2009}+\frac{7}{2011}}=\frac{-6.\left(\frac{1}{5}+\frac{1}{35}+\frac{1}{125}+\frac{1}{2009}+\frac{6}{2011}\right)}{7.\left(\frac{1}{5}+\frac{1}{35}+\frac{1}{125}+\frac{1}{2009}+\frac{1}{2011}\right)}\)\(=\frac{-6}{7}\)
đề sai nhé đề như mik ms đúng đi lm tiếp
Câu b thì sao bạn ơi??