Tính nhanh
1. 2100+299+298+297+.......+22+2
2. A=4/5.7 + 4/7.9 +......+4/59.61
3. C= 1/10.11+1/11.12 +......+ 1/99.100
4. D=5/11.16 + 5/16.21 + ......+5/61.66
5. 2100-299+298-297
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a) \(A=1+2+2^2+...+2^{50}\)
\(\Rightarrow2A=2+2^2+...+2^{51}\)
\(\Rightarrow A=2A-A=2+2^2+...+2^{51}-1-2-2^2-...-2^{50}=2^{51}-1\)
b) \(B=1+3+3^2+...+3^{100}\)
\(\Rightarrow3B=3+3^2+...+3^{101}\)
\(\Rightarrow2B=3B-B=3+3^2+...+3^{101}-1-3-3^2-...-3^{100}=3^{101}-1\)
\(\Rightarrow B=\dfrac{3^{101}-1}{2}\)
c) \(C=5+5^2+...+5^{30}\)
\(\Rightarrow5C=5^2+5^3+...+5^{31}\)
\(\Rightarrow4C=5C-C=5^2+5^3+...+5^{31}-5-5^2-...-5^{30}=5^{31}-5\)
\(\Rightarrow C=\dfrac{5^{31}-5}{4}\)
d) \(D=2^{100}-2^{99}+2^{98}-...+2^2-2\)
\(\Rightarrow2D=2^{101}-2^{100}+2^{99}-...+2^3-2^2\)
\(\Rightarrow3D=2D+D=2^{101}-2^{100}+2^{99}-...+2^3-2^2+2^{100}-2^{99}+...+2^2-2=2^{101}-2\)
\(\Rightarrow D=\dfrac{2^{101}-2}{3}\)
\(A=2^{100}-\left(2^{99}+2^{98}+...+2+1\right)\)
Đặt \(B=2^{99}+2^{98}+...+2+1\)
\(\Rightarrow2B=2^{100}+2^{99}+...+2^2+2\)
\(\Rightarrow2B-B=2^{100}-1\Leftrightarrow B=2^{100}-1\)
\(\Rightarrow A=2^{100}-\left(2^{100}-1\right)=1\)
tham khảo
https://olm.vn/hoi-dap/tim-kiem?q=A=2100-299-298-297-.........-22-2-1+.+t%C3%ADnh+A&id=52301
\(A=2^{100}-2^{99}-2^{98}-...-2\)
\(\Rightarrow-2A=-2^{101}+2^{100}+2^{99}+...+2^2\)
\(\Rightarrow A-2A=2^{100}-2^{99}-...-2-2^{101}+2^{100}+...2^2\)
\(\Rightarrow-A=2^{100}+2^{100}-2^{101}-2\)
\(\Rightarrow-A=-2\Rightarrow A=2\)
Ta có: \(A=2^{100}-2^{99}-2^{98}-...-2^2-2-1\)
\(\Leftrightarrow2A=2^{101}-2^{100}-2^{99}-...-2^3-2^2-2\)
\(\Leftrightarrow2A-A=2^{101}-2^{100}-2^{99}-...-2^3-2^2-2-2^{100}+2^{99}+2^{98}+...+2^2+2+1\)
\(\Leftrightarrow A=2^{101}-2\cdot2^{100}+1\)
\(\Leftrightarrow A=1\)
1+2-3-4+5+6-7-8 +.............+297+298-299-300
= (1+2)-(3+4)+(5+6-(7+8)+.........+(297+298)-(299+300)
=3-7+11-15+.......+595-599
= (3+11+......+595)-(7+15+...........+599)
=22425-22725
= (-300)
P/s: làm từng phần một
1.
\(2A=2^2+2^3+...+2^{101}\)
\(2A-A=\left(2^2+2^3+...+2^{101}\right)-\left(2+2^2+...+2^{100}\right)\)
\(A=2^{101}-2\)
2.
\(\frac{A}{2}=\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+...+\frac{2}{59\cdot61}\)
\(\frac{A}{2}=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{59}-\frac{1}{61}\)
\(\frac{A}{2}=\frac{1}{5}-\frac{1}{61}\)
\(\frac{A}{2}=\frac{56}{305}\)
\(A=\frac{112}{305}\)