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I
1 A
2C
3 B
4 D
5 B
II
1 D
2 B
3 B
4 B
5 A
6 D
7 B
8 B
9 D
10 A
III
1 leaving => left
2 Do => would
3 visit => visiting
4 play => playing
3 careless
4 bleed
V
1 Hung has colllected stamps since 2000
2 The front yard isn't large enough to play soccer in
3 Milk is delivered twice a week by the milkman
4 When did you bought this computer?
5 His car doesn't run as fasst as a race car
6 Two languages can be spoken well by Lan
VI
1 T
2 F
3 T
4 T
VII
1 Mr. Nam is arriving in Hue tonight
2 They are going back to Englang in two months
3 It is not difficult to tránlate this sentence into English
4 Would you mind lending me your dictionary?
Bài này giải ở dưới r đó
3 careless
4 bleed
V
1 Hung has colllected stamps since 2000
2 The front yard isn't large enough to play soccer in
3 Milk is delivered twice a week by the milkman
4 When did you bought this computer?
5 His car doesn't run as fasst as a race car
6 Two languages can be spoken well by Lan
VI
1 T
2 F
3 T
4 T
VII
1 Mr. Nam is arriving in Hue tonight
2 They are going back to Englang in two months
3 It is not difficult to tránlate this sentence into English
4 Would you mind lending me your dictionary?
3 careless
4 bleed
V
1 Hung has colllected stamps since 2000
2 The front yard isn't large enough to play soccer in
3 Milk is delivered twice a week by the milkman
4 When did you bought this computer?
5 His car doesn't run as fasst as a race car
6 Two languages can be spoken well by Lan
VI
1 T
2 F
3 T
4 T
VII
1 Mr. Nam is arriving in Hue tonight
2 They are going back to Englang in two months
3 It is not difficult to tránlate this sentence into English
4 Would you mind lending me your dictionary?
a: Áp dụng định lí Pytago vào ΔADC vuông tại D, ta được:
\(AC^2=AD^2+DC^2\)
\(\Leftrightarrow AC^2=8^2+15^2=289\)
hay AC=17cm
b: Áp dụng hệ thức lượng trong tam giác vuông vào ΔADC vuông tại D có DM là đường cao ứng với cạnh huyền AC, ta được:
\(DM\cdot AC=AD\cdot DC\)
\(\Leftrightarrow DM=\dfrac{120}{17}\left(cm\right)\)
a ) Theo định lý py-ta-go trong ΔADC, ta có :
AC^2 = AD^2 + CD^2
= 8^2 + 15^2
= 64 + 225
= 289
=> AC = 17 (cm)
b ) Ta có :
Xét tam giác ΔMDA và ΔDCA, có :
góc A chung
góc AMD = góc ADC = 90 độ
=> ΔMDA ∼ ΔDCA (G.G)
=> MD/CD = AD/AC
=> MD = CD.AD/AC
= 15.8/17
= 7,1 (cm)
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