Question

[Lê Phương Anh]

mn giúp mik vs ạ mik cảm ơn nhiều :)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(x^3+8=\left(x+2\right)\left(x^2-2x+4\right)\)

b: \(27y^3+1=\left(3y+1\right)\left(9y^2-3y+1\right)\)

c: \(x^3-27=\left(x-3\right)\left(x^2+3x+9\right)\)

d: \(x^3-1=\left(x-1\right)\left(x^2+x+1\right)\)

e: \(8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)\)

f: \(27x^3+64y^3=\left(3x+4y\right)\left(9x^2-12xy+16y^2\right)\)

g: \(x^3-\dfrac{1}{8}=\left(x-\dfrac{1}{2}\right)\left(x^2+\dfrac{1}{2}x+\dfrac{1}{4}\right)\)

Answer 2

[Lê Phương Anh]

cảm ơn bạn :)