giúp mik vs , càng nhanh cang tốt
chia đông từ.They are ...(have) breakfast on the table.
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BG
0
P
5 tháng 4 2020
1. was
2. got
3. did
4. took
5. combed
6. had
7. ate
8. drank
9. helped
10. brushed
11. put
12. went
13. had
14. returned
15. did
16. ate
17. took
18. was
19. came
went
CS
5 tháng 4 2020
IV. Use the correct form of the verbs and answer the question( Chia động từ trong ngoặc
và trả lời các câu hỏi )
Yesterday (be).was......... Sunday, Nam (get)....got...........up at six. He (do) ..did.........his morning
exercises. He (take) ...took............a shower (comb)...combed...........hair, and then he (have) ....had..........
breakfast with his parents. Nam (eat)...ate......... a bowl of noodles and (drink) .drank........a glass of milk for his breakfast. After breakfast, he (help) ..helped............Mom clean the table. After that, he
(brush)..brushed........ his teeth, (put)...put....... on clean clothes, and (go)...went......... to his grandparents'house. He (have).....had.........lunch with his grandparents. He (return) returned to his house at three o'lock. He (do)...did...........his homework. He (eat)..ate........ dinner at 6.30. After dinner, his parents (take).took......... him to the movie theater. It (be)...was............a very interesting film. They (come)..comed............back home at 9.30. Nam (go).....went.............. to bed at ten o'clock.
iúp mình vs càng nhanh càng tốt ạ
22 tháng 12 2021
\(a,\dfrac{x}{3x+6}=\dfrac{x}{3\left(x+2\right)}=\dfrac{x\left(x+2\right)}{3\left(x+2\right)^2}\\ \dfrac{5}{x^2+4x+4}=\dfrac{5}{\left(x+2\right)^2}=\dfrac{15}{3\left(x+2\right)^2}\\ b,\dfrac{5}{x^2-y^2+2x+1}=\dfrac{5}{\left(x-y+1\right)\left(x+y+1\right)}=\dfrac{5x}{x\left(x-y+1\right)\left(x+y+1\right)}\\ \dfrac{6}{x\left(x+y+1\right)}=\dfrac{6\left(x-y+1\right)}{x\left(x-y+1\right)\left(x+y+1\right)}\)
\(c,\dfrac{7x}{x^4-1}=\dfrac{7x}{\left(x^2+1\right)\left(x-1\right)\left(x+1\right)}=\dfrac{7x\left(x^2+1\right)}{\left(x^2+1\right)\left(x-1\right)\left(x+1\right)}\\ \dfrac{5x}{x^4+2x^2+1}=\dfrac{5x}{\left(x^2+1\right)^2}=\dfrac{5x\left(x-1\right)\left(x+1\right)}{\left(x^2+1\right)^2\left(x-1\right)\left(x+1\right)}\)
They are having (have) breakfast on the table.
They are have breakfast on the table.
( mình thắc mắc một cái là tại sao lại là they are, phải they have mới đúng chứ )