tinh rut gon
\(\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{2^2\cdot3^{28}}\)
K
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CN
1
29 tháng 9 2016
\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
=\(\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)
=\(\frac{11\cdot3^{29}-3^{29}\cdot3}{2^2\cdot3^{28}}\)
=\(\frac{3^{29}\cdot\left(11-3\right)}{2^2\cdot3^{28}}\)
=\(\frac{3^{29}\cdot2^3}{2^2\cdot3^{28}}\)
=\(\frac{3\cdot2}{1}\)
=6
TB
4
29 tháng 9 2016
\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(A=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(A=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)
\(A=\frac{3^{29}.8}{4.3^{28}}=3.2=6\)
T
2
28 tháng 7 2017
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(=3.2=6\)
9 tháng 10 2018
\(A=\frac{3^7\cdot17-3^9}{2^3\cdot3^5}=\frac{3^7\left(17-3^2\right)}{2^3\cdot3^5}=\frac{3^7\cdot2^3}{2^3\cdot3^5}=9\)
\(B=\frac{3^2\cdot4^2\cdot2^{32}}{11\cdot2^{13}\cdot4^{11}-16^9}=\frac{3^2\cdot2^{36}}{2^{35}\cdot11-2^{36}}=\frac{3^2\cdot2^{36}}{2^{35}\left(11-2\right)}=\frac{3^2\cdot2^{36}}{2^{35}\cdot3^2}=2\)
9 tháng 10 2018
\(\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2\cdot3^{28}}=\frac{3^{29}\cdot8}{2^2\cdot3^{28}}=6\)
19 tháng 7 2017
\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\dfrac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(=\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(=\dfrac{3^{29}\left(11-3\right)}{2^2.3^{28}}\)
\(=\dfrac{3^{29}.2^3}{2^2.3^{28}}\)
\(=\dfrac{3.2}{1.1}=6\)
F
28 tháng 2 2020
Bài giải
a, \(\frac{7}{12}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{12}\)
\(=\left(\frac{7}{12}-\frac{5}{12}+\frac{5}{6}+\frac{1}{4}\right)-\frac{3}{7}=\left(\frac{7}{12}-\frac{5}{12}+\frac{10}{12}+\frac{3}{12}\right)-\frac{3}{7}=\frac{5}{4}-\frac{3}{7}=\frac{23}{28}\)
b, \(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{3^{28}\cdot4}=\frac{3\cdot8}{4}=6\)
\(\dfrac{11.3^{22}.3^7-9^{15}}{2^2.3^{28}}\)
\(=\dfrac{11.3^{28}.3-9^{15}}{2^2.3^{28}}\)
\(=\dfrac{11.3-9^{15}}{2^2}\)
\(=\dfrac{33-9^{15}}{4}\)
\(\dfrac{11.3^{22}.3^7-9^{15}}{2^2.3^{28}}\)
=\(\dfrac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
=\(\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
=\(\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
=\(\dfrac{3^{29}.8}{2^2.3^{28}}\)
=\(\dfrac{3^{29}.2^3}{2^2.3^{28}}\)
=3.2
=6