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11 tháng 8 2017

Ta có:

\(\dfrac{1}{20}=\dfrac{1}{4}-\dfrac{1}{5}\)

\(\dfrac{1}{14}=\dfrac{1}{10}-\dfrac{1}{35}\)

\(\dfrac{1}{56}=\dfrac{1}{7}-\dfrac{1}{8}\)

Thay vào ta được:

\(2 + \dfrac{1}{4}+ \dfrac{3}{4} - \dfrac{3}{5}+\dfrac{1}{10} + \dfrac{1}{10} - \dfrac{1}{35}+ \dfrac{3}{7} - \dfrac{3}{8} + \dfrac{1}{24} \)

\(= 3 - \dfrac{2}{5} - \dfrac{1}{35} + \dfrac{3}{7} - \dfrac{3}{8}+ \dfrac{1}{24} \)

\(= 3 + \dfrac{1}{35} - \dfrac{1}{35} + \dfrac{1}{24} - \dfrac{3}{8} \)

\(= 3 + \dfrac{1}{24} - \dfrac{3}{8}\)

\(= 2 + \dfrac{5}{8}+ \dfrac{1}{24} \)

\(= 2 + \dfrac{1}{8} (5 + \dfrac{1}{3}) \)

\(= 2 + \dfrac{16}{24} \)

\(=2+\dfrac{2}{3}\)

\(=\dfrac{8}{3}\)

22 tháng 8 2018

a) 39                    b) 20                        c) 29                       d) ...

1: \(=\dfrac{1}{29\cdot30}-\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{28\cdot29}\right)\)

\(=\dfrac{1}{29\cdot30}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{28}-\dfrac{1}{29}\right)\)

\(=\dfrac{1}{29\cdot30}-\dfrac{28}{29}=\dfrac{1-28\cdot30}{870}=\dfrac{-859}{870}\)

Bài 1: 

a: -8/12<0<-3/-4

b: -56/24<0<7/3

c: 4/25<1<15/13

=>-4/25>-15/13

Bài 2: 

a: =-60/45=-4/3

b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6

11 tháng 12 2022

b

 

 
a  
c  

 

3 tháng 3 2023

`4/7+4`

`=4/7+4/1`

`=4/7+28/7`

`=32/7`

__

`3+6/11`

`=33/11+6/11`

`=39/11`

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`3-5/7`

`=3/1-5/7`

`=21/7-5/7`

`=16/7`

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`21/9-2`

`=21/9-18/9`

`=3/9`

`=1/3`

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`15/24+2`

`=15/24+48/24`

`=63/24`

`=21/16`

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`63/45-20/25`

`=63/45-4/5`

`=63/45-36/45`

`=27/45`

`=9/15`

__

`3/4-2/8`

`=3/4-1/4`

`=2/4`

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`6/7-5/8`

`=48/56-35/56`

`=13/56`

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`37/45-5/9`

`=37/45-25/45`

`=12/45`

`=4/15`

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`46/39-11/13`

`=46/39-33/39`

`=13/39`

`=1/2`

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`5/12+3/4+1/3`

`=5/12+9/12+4/12`

`=14/12+4/12`

`=18/12`

`=3/2`

__

`1/2+3/7+11/14`

`=7/14+6/14+11/14`

`=13/14+11/14`

`=24/14`

`=12/7`

__

`7/10-(1/5+1/4)`

`=7/10-(4/20+5/20)`

`=7/10-9/20`

`=14/20-9/20`

`=5/20`

`=1/4`

__

`15/4-2/3-3/4`

`=(15/4-3/4)-2/3`

`=12/4-2/3`

`=3-2/3`

`=9/3-2/3`

`=7/3`