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4 tháng 8 2017

A = \(\dfrac{72^3.5^{42}}{108^4}\)

= \(\dfrac{\left(2^3.3^2\right)^3.5^{42}}{\left(2^2.3^3\right)^4}\)

= \(\dfrac{2^9.3^6.5^{42}}{2^8.3^{12}}\)

= \(\dfrac{2.5^{42}}{3^6}\)

@trần phúc nguyên

4 tháng 8 2017

B = \(\dfrac{45^3.20^4.18^2}{180^5}\)

= \(\dfrac{\left(3^2.5\right)^3\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)

= \(\dfrac{3^6.5^3.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)

= \(\dfrac{3^{10}.5^7.2^{10}}{2^{10}.3^{10}.5^5}\)

= 25
@trần phúc nguyên

25 tháng 9 2017

453 = (9.5)3 = 36.53

204 = (4.5)4 = 28.54

182 = (9.2)2 = 34.22

1805 = (4.9.5)5 = 210.310.55

\(=\dfrac{3^6.5^3.2^8.5^4.3^4.2^2}{2^{10}.3^{10}.5^5}=\dfrac{2^{10}.3^{10}.5^7}{2^{10}.3^{10}.5^5}=5^2=25\)

25 tháng 9 2017

\(B=\dfrac{11.3^{29}-3^{30}}{4.3^{28}}=\dfrac{3^{29}\left(11-3\right)}{3^{28}.4}=\dfrac{3.8}{4}=6\)

1 tháng 8 2020

\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.16}{3^9.16}=3\)

\(B=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^{10}.26.3}{2^8.2^2.26}=3\)

\(C=\frac{72^3.52^4}{108^4}=\frac{\left(3^2.2^3\right)^3.\left(13.2^2\right)^4}{\left(3^3.2^2\right)^4}=\frac{3^6.2^9.13^4.2^8}{3^{12}.2^8}=\frac{2^9.13^4}{3^6}\)

\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(33-1\right)}{2^2.3^{28}}=\frac{3^{29}.2^5}{2^2.3^{28}}=3.8=24\)

mấy bn lm giúp mk nha , mk tk cho 3 tk 

a: \(=\dfrac{2^{12}\cdot3^{14}}{3^{12}\cdot2^{12}}=3^2=9\)

b: \(=\dfrac{7^3\cdot2\cdot5^3}{5^2\cdot7^2\cdot6}=7\cdot5\cdot\dfrac{1}{3}=\dfrac{35}{3}\)

d: =2^5(2^8+1)/2^2(2^8+1)=2^3=8

c: \(=\dfrac{5^3\cdot3^6\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}=5^2\)

25 tháng 6 2016

B = 11 . 322 . 37 - 915 / (2 . 314)2

B = 11 . 329 - (32)15 / 22 . 328

B = 11 . 329 - 330 / 22 . 328

B = 329 . (11 - 3) / 22 . 328

B = 329 . 8 / 22 . 328

B = 329 . 23 / 22 . 328

B = 3 . 2

B = 6

25 tháng 7 2017

\(\frac{45^3.20^4.18^2}{180^5}=\frac{\left(3^2.5\right)^3.\left(2^2x5\right)^4.\left(2x3^2\right)^2}{\left(2^2.3^2.5\right)^5}\) 

                           \(=\frac{3^6.5^3.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)\(=\frac{3^{10}.5^7.2^{10}}{2^{10}.3^{10}.5^5}=\frac{5^7}{5^5}=5^2\)