Tìm x
a)346.124 - 7.(2x - 1 ) = 346
b)4/3 + 2.(5+7x)=115:5
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giao cho mik
a)346.124 - 7.(2x - 1 ) = 346
42904 - 7.(2x - 1 ) = 346
7.(2x - 1 ) = 42904 - 346
7.(2x - 1 ) = 42558
2x - 1 = 42558 :7
2x - 1 = 42558/7
2x = 42558/7+1
2x = 42565/7
x = 42565/7:2
x = 42565/14
a)346.124 - 7.(2x - 1 ) = 346
42904 - 7.(2x - 1 ) = 346
7.(2x - 1 ) = 42904 - 346
7.(2x - 1 ) = 42558
2x - 1 = 42558 :7
2x - 1 = 42558/7
2x = 42558/7+1
2x = 42565/7
x = 42565/7:2
x = 42565/14
a) 7(2x-1)=(346.124)-346
14x-7=42558
14x=42551
x=42551/14
b) 4/3+2(5+7x)=23
2(5+7x)=65/3
5+7x=65/6
7x=35/6
x=5/6
a) 346.124-7.(2x-1)=343
346.124-14x+7=343
42904-14x+7=343
-14x=343-42904-7
-14x=-42568
x=\(\dfrac{-42568}{-14}\)=\(\dfrac{42568}{14}\)=3,04
vậy x = 3,04
b)\(\dfrac{4}{3}\)+2(5+7x)=115:5
\(\dfrac{4}{3}\)+10+14x=23
14x=23-10-\(\dfrac{4}{3}\)
14x= \(\dfrac{35}{3}\)
x=\(\dfrac{35}{3}\):14
x=\(\dfrac{35}{42}\)=\(\dfrac{5}{6}\)
a:\(\Leftrightarrow7\left(2x-1\right)=346\cdot124-346=42558\)
=>2x-1=42558/7
=>2x=42565/7
hay x=42565/14
b: \(\Leftrightarrow2\left(7x+5\right)=23-\dfrac{4}{3}=\dfrac{65}{3}\)
=>7x+5=65/6
=>7x=35/6
hay x=5/6
a) ( 2x - 3 ) - ( x - 5 ) = ( x + 7 ) - ( x + 2 )
<=> 2x - 3 - x + 5 = x + 7 - x - 2
<=> x = 3
b)(7x-5)-(6x+4)=(2x+3)-(2x+1)
<=> 7x - 5 - 6x - 4 = 2x + 3 - 2x - 1
<=> x = 11
c)(9x-3)-(8x+5)=(3x+2)
<=> 9x - 3 - 8x - 5 = 3x + 2
<=> -2x = 10
<=> x = -5
d)(x+7)-(2x+3)=(3x+5)-(2x+4)
<=> x + 7 - 2x - 3 = 3x + 5 - 2x - 4
<=> -2x = -3
<=> x = 3/2
a) 5(2x -1) - 4(8 - 3x) = 7
<=> 10x - 5 - 32 + 12x = 7
<=> 22x = 44
<=> x =2
Vậy x = 2 là nghiệm phương trình
b) 7(2x - 5) - 5(7x - 2) + 2(5x - 7) = (x - 2) - (x + 4)
<=> 14x - 35 - 35x + 10 + 10x - 14 = x - 2 - x - 4
<=> -11x - 39 = - 6
<=> -11x = 33
<=> x = -3
Vậy x = -3 là nghiệm phương trình
\(a,10x-5-32+12x=7\)
\(22x=44\)
\(x=2\)
\(b,14x-35-35x+10+10x-14=x-2-x-4\)
\(-11x-39=-6\)
\(-11x=-33\)
\(x=3\)
a) 2x - 5 = 3 + 2x - 7x
=> 2x - 2x + 7x = 3 +5
=> 7x = 8
=> x = 8/7
b) \(\left(2x-1\right)^2=\left(2x-1\right)^5\)
=> \(\left(2x-1\right)^2-\left(2x-1\right)^5=0\)
=> \(\left(2x-1\right)^2\left[1-\left(2x-1\right)^3\right]=0\)
=> \(\orbr{\begin{cases}\left(2x-1\right)^2=0\\1-\left(2x-1\right)^3=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x-1=0\\\left(2x-1\right)^3=1\end{cases}}\)
=> \(\orbr{\begin{cases}2x=1\\2x-1=1\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{1}{2}\\2x=2\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{1}{2}\\x=1\end{cases}}\)
\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)
a ) \(-5\times\left(-x+7\right)-3\times\left(-x-5\right)=-4\times\left(12-x\right)+48\)
\(\Leftrightarrow5x-35+3x+15=-48+4x+48\)
\(\Leftrightarrow5x-3x+4x=35-15-48+48\)
\(\Leftrightarrow2x=20\)
\(\Leftrightarrow x=10\)
b ) \(-2\times\left(15-3x\right)-4\times\left(-7x+8\right)=-5-9\times\left(-2x+1\right)\)
\(\Leftrightarrow-30+6x-28x-32=-5+18x-9\)
\(\Leftrightarrow6x-28x-18x=30+32-5-9\)
\(\Leftrightarrow-40x=48\)
\(\Leftrightarrow x=-1.2\)
Tìm x :
346 . 124 - 7 . ( 2x - 1 ) = 346
7 . ( 2x - 1 ) = ( 346 . 124 ) - 346
7. ( 2x - 1 ) = 346 . 123
7 . 2x - 7 .1 = 42558
7 . 2x = 42558 - 7
7.2. x = 42551
14 . x = 42551
=> x = \(\dfrac{42551}{14}\)
Vậy : x = \(\dfrac{42551}{14}\)
b) \(\dfrac{4}{3}\) +2 . ( 5 + 7x ) = 115 : 5
\(\dfrac{4}{3}\) + 2. 5 + 2 . 7.x = 23
\(\dfrac{4}{3}\) + 10 + 14 . x = 23
\(\dfrac{4}{3}\) + 24 . x = 23
=> \(\dfrac{76}{3}\) . x = 23
=> x = 23 : \(\dfrac{76}{3}\)
=> x = \(\dfrac{69}{76}\)
Vậy x = \(\dfrac{69}{76}\)