Tim x
a.346.124-7.(2x-1)=346
b.4/3+2.(5+7x)=115:5
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a:\(\Leftrightarrow7\left(2x-1\right)=346\cdot124-346=42558\)
=>2x-1=42558/7
=>2x=42565/7
hay x=42565/14
b: \(\Leftrightarrow2\left(7x+5\right)=23-\dfrac{4}{3}=\dfrac{65}{3}\)
=>7x+5=65/6
=>7x=35/6
hay x=5/6
Tìm x :
346 . 124 - 7 . ( 2x - 1 ) = 346
7 . ( 2x - 1 ) = ( 346 . 124 ) - 346
7. ( 2x - 1 ) = 346 . 123
7 . 2x - 7 .1 = 42558
7 . 2x = 42558 - 7
7.2. x = 42551
14 . x = 42551
=> x = \(\dfrac{42551}{14}\)
Vậy : x = \(\dfrac{42551}{14}\)
b) \(\dfrac{4}{3}\) +2 . ( 5 + 7x ) = 115 : 5
\(\dfrac{4}{3}\) + 2. 5 + 2 . 7.x = 23
\(\dfrac{4}{3}\) + 10 + 14 . x = 23
\(\dfrac{4}{3}\) + 24 . x = 23
=> \(\dfrac{76}{3}\) . x = 23
=> x = 23 : \(\dfrac{76}{3}\)
=> x = \(\dfrac{69}{76}\)
Vậy x = \(\dfrac{69}{76}\)
giao cho mik
a)346.124 - 7.(2x - 1 ) = 346
42904 - 7.(2x - 1 ) = 346
7.(2x - 1 ) = 42904 - 346
7.(2x - 1 ) = 42558
2x - 1 = 42558 :7
2x - 1 = 42558/7
2x = 42558/7+1
2x = 42565/7
x = 42565/7:2
x = 42565/14
a)346.124 - 7.(2x - 1 ) = 346
42904 - 7.(2x - 1 ) = 346
7.(2x - 1 ) = 42904 - 346
7.(2x - 1 ) = 42558
2x - 1 = 42558 :7
2x - 1 = 42558/7
2x = 42558/7+1
2x = 42565/7
x = 42565/7:2
x = 42565/14
a) 2x + 23x = 625
x (2 + 23) = 625
x. 25 = 625
x = 625 : 25
x = 25
b) (2^2+4^2) x +2^4 x 5 * x = 100 (dấu* là dấu nhân vì mik không muốn trùng nhau nên viết vậy)
( 4 + 16 ) x + 2^4 x 5 * x = 100
20 * x + 16 x 5 * x =100
x ( 20 + 16 x 5 ) = 100
x ( 20 + 80 ) = 100
x * 100 =100
x=100 : 100
x= 1
c) ( 3x +1)^2 = 6^2+8^2
(3x +1)^2 = 36 +64
(3x +1)^2 =100
(3x +1)^2 = 10^2
3x + 1 =10
3x=10 - 1=9
x = 9 :3
x = 3
( d và e làm tương tự )
k mik nha!
a) Đặt x^2+2x+2=t
\(\frac{4}{t-1}+\frac{3}{t+1}=\frac{3}{2}\Leftrightarrow\frac{4t+4+3t-3}{t^2-1}=\frac{7t+1}{t^2-1}=\frac{3}{2}\)
\(\Leftrightarrow14t+2=3t^2-3\Leftrightarrow3t^2-14t-5=3t\left(t-5\right)+t-5=0\)\(\Leftrightarrow\left(t-5\right)\left(3t+1\right)=0\Rightarrow\left[\begin{matrix}t=5\\t=-\frac{1}{3}\left(loai\right)\end{matrix}\right.\)
Với t=5 ta có (x+1)^2=4\(\Rightarrow\left[\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=1\\x=-3\end{matrix}\right.\)
\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)
`a,4x-10=0 `
`<=> 4x=10`
`<=>x=10/4`
`<=>x=5/2`
`b, 7-3x=9-x `
`<=>-3x+x=9-7`
`<=>-2x=2`
`<=>x=-1`
`c, 2x-(3-5x) = 4(x+3)`
`<=>2x-3+5x=4x+12`
`<=>2x+5x-4x=12+3`
`<=>3x=15`
`<=>x=5`
`d, 5-(6-x)=4(3-2x) `
`<=>5-6+x=12-8x`
`<=>x+8x=12-5+6`
`<=>9x=13`
`<=>x=13/9`
`e, 4(x+3)=-7x+17 `
`<=>4x+12=-7x+17`
`<=>4x+7x=17-12`
`<=>11x=5`
`<=>x=5/11`
`f, 5(x-3) - 4=2(x-1)+7`
`<=>5x-15-4=2x-2+7`
`<=>5x-2x=15+4-2+7`
`<=>3x=24`
`<=>x=8`
`g, 5(x-3)-4=2(x-1)+7 `
`<=>5x-15-4=2x-2+7`
`<=>5x-2x=15+4-2+7`
`<=>3x=24`
`<=>x=8`
`h,4(3x-2)-3(x-4)=7x+20`
`<=>12x-8-3x+12=7x+20`
`<=>12x-3x-7x=20+8+12`
`<=>2x=40`
`<=>x=20`
Bài 2:
a: \(\Leftrightarrow\left(x-2\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
a) 7(2x-1)=(346.124)-346
14x-7=42558
14x=42551
x=42551/14
b) 4/3+2(5+7x)=23
2(5+7x)=65/3
5+7x=65/6
7x=35/6
x=5/6
a) 346.124-7.(2x-1)=343
346.124-14x+7=343
42904-14x+7=343
-14x=343-42904-7
-14x=-42568
x=\(\dfrac{-42568}{-14}\)=\(\dfrac{42568}{14}\)=3,04
vậy x = 3,04
b)\(\dfrac{4}{3}\)+2(5+7x)=115:5
\(\dfrac{4}{3}\)+10+14x=23
14x=23-10-\(\dfrac{4}{3}\)
14x= \(\dfrac{35}{3}\)
x=\(\dfrac{35}{3}\):14
x=\(\dfrac{35}{42}\)=\(\dfrac{5}{6}\)