Cho B=1+5+52+53+...+596+597+598. Chứng tỏ B chia hết cho 31
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)
N
2
MT
6 tháng 8 2015
B= 1+ 5+ 5^2+ 5^3+ ... + 5^96+ 5^97+ 5^98
=(1+5+52)+(53+54+55)+....+(596+597+598)
=31+(53.1+53.5+53.52)+....+(596.1+597.5+598.52)
=31+53.(1+5+52)+....+596.(1+5+52)
=31.1+53.31+...+596.31
=31.(1+53+...+596)
=> B chia hết cho 31
HT
6 tháng 8 2015
B = 1+5+52+53+....+598
B = (1+5+52)+(53+54+55)+....+(596+597+598)
B = 1(1+5+52)+53(1+5+52)+....+596(1+5+52)
B = 1.31 + 53.31+.......+596.31
B = 31.(1+53+.....+596) chia hết cho 31 (đpcm)
DN
5 tháng 11 2020
Giải:
a) A = 21 + 22 + 23 + 24 + .............. + 22010
Ta có :
Trong 1 tích chỉ cần có 1 số chia hết cho n thì tích đó chia hết cho n mà 21 \(⋮\)cả 3 và 7
=> A \(⋮\)cả 3 và 7
Vây A \(⋮\)cả 3 và 7
b) B = 31 + 32 + 33 + 34 + ............... + 22010
Ta có :
Trong 1 tích chỉ cần có 1 số chia hết cho n thì tích đó chia hết cho n
mà 32 \(⋮\)4
Vì dãy số trên là các số tự nhiên có khoảng cách là 1 nên 39 nằm trong dãy số đó mà 39 \(⋮\)13
=> B \(⋮\)cả 4 và 13
Vậy B \(⋮\)cả 4 và 13
c) C = 51 + 52 + 53 + 54 + ................... + 52010
Ta có :
Trong 1 tích chỉ cần có 1 số chia hết cho n thì tích đó chia hết cho n
mà 54 \(⋮\)6
Vì dãy số trên là các số tự nhiên có khoảng cách là 1 nên 62 nằm trong dãy số đó mà 62 \(⋮\)31
=> C \(⋮\)cả 6 và 31
Vậy C \(⋮\)cả 6 và 31
d) D = 71 + 72 + 73 + 74 + ...................... + 72010
Ta có :
Trong 1 tích chỉ cần có 1 số chia hết cho n thì tích đó chia hết cho n
mà 72 \(⋮\)8
Vì dãy số trên là các số tự nhiên có khoảng cách là 1 nên 114 nằm trong dãy số đó mà 114 \(⋮\)57
=> D \(⋮\)cả 8 và 57
Vậy D \(⋮\)cả 8 và 57
Học tốt!!!
TN
16 tháng 5 2016
a)abc chia hết 27
=>abc chia hết 3 và 9
mà abc chia hết 9 thì 100% chia hết 3
mà abc chia hết 9=>(a+b+c) chia hết 9
=>(b+c+a=a+b+c) chia hết 9 => bca chia hết 3
=>bca chia hết 27
16 tháng 5 2016
a ) vì abc chia hết cho 27
=> bca chia hết cho 27 ( hiển nhiên đúng )
LM
1
8 tháng 10 2017
\(A=1+5^1+5^2+...+5^{101}\)
\(A=\left(1+5^1+5^2\right)+...+\left(5^{99}+5^{100}+5^{101}\right)\)
\(A=\left(1+5^1+5^2\right)+...+5^{99}.\left(1+5^1+5^2\right)\)
\(A=31+...+5^{99}.31\)
\(A=31.\left(1+...+5^{99}\right)⋮31\left(đpcm\right)\)
LT
0
1+5+5^2+...+5^99=(1+5+5^2)+5^3x(1+5+5^2)+5^6x(1+5+5^2)+...+5^97x(1+5+5^2) [vì có 99 số hạng chia hết cho 3]
=31+5^3x31+5^6x31+...+5^97x31=(1+5^3+5^6+...+5^97)x31 chia hết cho 31
B=1+5+52+53+...+596+597+598
=(1+5+52)+(53+54+55)+...+(596+597+598)
=31+53.(1+5+52)+...+596.(1+5+52)
=31+53.31+...+596.31
=31.(1+53+...+596)
=>B chia hết cho 31