Thực hiện các phép tính : \(\left(-476\right)-53\), ta được :
(A) \(\left(-1006\right)\) (B) \(1006\) (C) \(\left(-529\right)\) (D) \(\left(-423\right)\)
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Ta có: (- 476) - 53 = (-476) + (-53) = - ( 476 + 53) = - 529
Chọn đáp án (C) (-529).
\(B=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)...\left(2^{1006}+1\right)+1\)
\(\Leftrightarrow B=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)...\left(2^{1006}+1\right)+1\)
\(\Leftrightarrow B=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)...\left(2^{1006}+1\right)+1\)
\(\Leftrightarrow B=\left(2^4-1\right)\left(2^4+1\right)...\left(2^{1006}+1\right)+1\)
................................
................................
\(\Rightarrow B=\left(2^{1006}-1\right)\left(2^{1006}+1\right)+1=2^{2012}-1+1=2^{2012}\)
Không hiểu chỗ nào thì hỏi nhé
B = 1.(2+1).(2^2+1). ...... .(2^1006+1)+1
= (2-1).(2+1).(2^2+1).(2^4+1).......(2^1006+1)+1
= (2^2-1).(2^2+1).(2^4+1)......(2^1006+1)+1
= (2^4-1).(2^4+1)......(2^1006+1)+1
.........
= (2^1006-1).(2^1006-1)+1
= 2^2012-1+1 = 2^2012
Tk mk nha
Sửa đề
\(B=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)...\left(2^{1024}+1\right)+1\)
\(=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)...\left(2^{1024}+1\right)+1\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)...\left(2^{1024}+1\right)+1\)
\(..................................................\)
\(=\left(2^{1024}-1\right)\left(2^{1024}+1\right)+1\)
\(=2^{2048}-1+1=2^{2048}\)
a) \(-0,8\sqrt{\left(-0,125\right)^2}=-0,8.\left|-0,125\right|=-0.8.0,125=-\dfrac{1}{10}\)
b) \(\sqrt{\left(-2\right)^6}=\sqrt{\left(\left(-2\right)^3\right)^2}=\left|\left(-2\right)^3\right|=8\)
c) \(\sqrt{\left(\sqrt{3}-2\right)^2}=\left|\sqrt{3}-2\right|=2-\sqrt{3}\)
d) \(\sqrt{\left(2\sqrt{2}-3\right)^2}=\left|2\sqrt{2}-3\right|=3-2\sqrt{2}\)
Đáp án C đúng
câu C