Bài 5 : Thực hiện các phép tính sau bằng cách hợp lý.
a) (2^17 + 17^2).(9^15 – 3^15).(2^4 – 4^2)
b) (8^2017 – 8^2015) : (8^2104.8)
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`a)3/5+(-4/9)`
`=3/5-4/9`
`=27/45-20/45`
`=7/45`
`b)3/5+2/5 . 15/8`
`=3/5 + 30/40`
`=3/5+3/4`
`=12/20+15/20`
`=27/20`
`c)7/2 . 8/13 + 8/13 . (-5/2)`
`=8/13 . (7/2 +(-5)/2)`
`=8/13 . 1`
`=8/13`
`d)-5/17 . (-9/23)+9/23 . (-22/17) + 11 9/23`
`=-5/17 . (-9/23) + 9/23 . (-1) . 22/17 + 11 + 9/23`
`=-5/17 . (-9/23) + (-9/23) . 22/17+11+9/23`
`= -9/23 ( -5/17 + 22/17)+11+9/23`
`= - 9/23 . 1+11+9/23`
`=-9/23+11+9/23`
`=(-9/23+9/23)+11`
`=0+11`
`=11`
a: =27/45-20/45=7/45
b: =3/5+30/40
=3/5+3/4
=12/20+15/20
=27/20
c: =8/13(7/2-5/2+1)=8/13*2=16/13
d: =9/23*5/17-9/23*22/17+11+9/23
=-9/23+11+9/23
=11
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
Bài 1 :
a) \(\left(2^{17}+17^2\right).\left(9^{15}-3^{15}\right).\left(2^4-4^2\right)\)
\(=\left(2^{17}+17^2\right).\left(9^{15}-3^{15}\right).\left(16-16\right)\)
\(=\left(2^{17}+17^2\right).\left(9^{15}-3^{15}\right).0\)
\(=0\)
câu b sai đề rồi bạn , mình sủa lại đề nha :
b) \(\left(8^{2017}-8^{2015}\right)\div\left(8^{2014}.8\right)\)
\(=\left(8^{2017}-8^{2015}\right)\div8^{2015}\)
\(=8^{2017}\div8^{2015}-8^{2015}\div8^{2015}\)
\(=8^2-1\)
\(=64-1\)
\(=63\)
c) \(\left(1^3+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).\left(3^8-81^2\right)\)
\(=\left(1^3+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).\left[3^8.\left(3^4\right)^2\right]\)
\(=\left(1^3+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).\left[3^8-3^8\right]\)
\(=\left(1^3+2^3+3^4+4^5\right).\left(1^3+2^3+3^3+4^3\right).0\)
\(=0\)
d) \(\left(2^8+8^3\right)\div\left(2^5.2^3\right)\)
\(=\left[2^8+\left(2^3\right)^3\right]\div2^8\)
\(=\left[2^8+2^9\right]\div2^8\)
\(=2^8\div2^8+2^9\div2^8\)
\(=1+2\)
\(=3\)
Bài 2 :
a) \(125^5\div25^3=\left(5^3\right)^5\div\left(5^2\right)^3=5^{15}\div5^6=5^9\)
b) \(27^6\div9^3=\left(3^3\right)^6\div\left(3^2\right)^3=3^{18}\div3^6=3^{12}\)
c) \(4^{20}\div2^{15}=\left(2^2\right)^{20}\div2^{15}=2^{40}\div2^{15}=2^{25}\)
d) \(24^n\div2^{2n}=24^n\div4^n=6^n\)
a
24-42=0
=>(217 + 172).(915 - 315).(24 - 42)=0
b
(71997 - 71995) : (71994.7)
=71995(72-1):71995=48
c) (12 + 23 + 34 + 45).(13+ 23 + 33 + 43).(38 - 812)
=(12 + 23 + 34 + 45).(13+ 23 + 33 + 43).0=0
d) (28 + 83) : (25.23)
=(28+29);28=3
\(\dfrac{4}{5}\)+\(\dfrac{-5}{4}\)=\(\dfrac{0}{4}\)
\(\dfrac{-1}{3}\)+\(\dfrac{2}{5}-\dfrac{5}{6}\)=\(\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}\)=\(\dfrac{-23}{30}\)
\(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}\)=\(\dfrac{2}{3}-\dfrac{2}{5}\)=\(\dfrac{10}{15}-\dfrac{6}{15}\)=\(\dfrac{4}{15}\)
a) ( 217 + 172 ) . ( 915 - 315 ) . ( 24 - 42 )
= ( 217 + 172 ) . ( 915 - 315 ) . ( 16 - 16 )
= ( 217 + 172 ) . ( 915 - 315 ) . 0
= 0
b) ( 82017 - 82015 ) : ( 82014 . 8 )
= 82015 . ( 82 - 1 ) : 82015
= 64 - 1
= 63