Tìm x, biết
a) x/4 = 21/28
b) 2x/5 = -24/ 10
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a) \(\frac{x}{4}=\frac{21}{28}\)
Ta có : \(\frac{21}{28}=\frac{21:7}{28:7}=\frac{3}{4}\)
\(\Rightarrow\frac{x}{4}=\frac{3}{4}\Rightarrow x=3\)
Vậy x = 3
b) \(\frac{2x}{5}=-\frac{24}{10}\)
Ta có : \(\frac{-24}{10}=\frac{-12}{5}\)
=> \(\frac{2x}{5}=-\frac{12}{5}\)
=> \(2x=-12\Rightarrow x=-6\)
Vậy x = - 6
\(a.\dfrac{6}{5}=\dfrac{18}{x}\Rightarrow x=\dfrac{18\cdot5}{6}=15\\ \text{Vậy}\text{ }x=15.\)
\(b.\dfrac{3}{4}=\dfrac{-21}{x}\Rightarrow x=\dfrac{-21\cdot4}{3}=28\\ \text{ }\text{ }\text{ }\text{ }\text{Vậy }x=28.\)
\(c.\dfrac{x}{4}=\dfrac{21}{28}\Rightarrow x=\dfrac{21\cdot4}{28}=3\\ \text{Vậy }x=3.\)
\(d.\dfrac{-8}{2x}=\dfrac{3}{-9}\Rightarrow x=\dfrac{-8\cdot\left(-9\right)}{3}:2=12\\ \text{Vậy }x=12.\)
\(e.\dfrac{-4}{11}=\dfrac{x}{22}=\dfrac{40}{z}\\ \Rightarrow x=\dfrac{-4\cdot22}{11}=-8\\ \Rightarrow z=\dfrac{22\cdot40}{-8}=-110\\ \text{Vậy }x=-8;z=-110.\)
\(f.\dfrac{-3}{4}=\dfrac{x}{20}=\dfrac{21}{y}\\ \Rightarrow x=\dfrac{-3\cdot20}{4}=-15\\ \Rightarrow y=\dfrac{21\cdot20}{-15}=-28\\ \text{Vậy }x=-15;y=-28.\)
\(g.\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\\ \Rightarrow x=\dfrac{-4\cdot\left(-10\right)}{8}=5\\ \Rightarrow y=\dfrac{-7\cdot\left(-10\right)}{5}=14\\ \Rightarrow z=\dfrac{-7\cdot\left(-24\right)}{14}=12\\ \text{Vậy }x=5;y=14;z=12.\)
\(h.\dfrac{x}{4}=\dfrac{9}{x}\\ \Rightarrow x\cdot x=9\cdot4\\ \Rightarrow x\cdot x=36\\ \Rightarrow x\cdot x=6\cdot6\\ \text{Vậy }\text{cả hai }x=6.\)
a)\(\frac{x}{4}=\frac{21}{28}\)
x . 28 = 4.21
x.28 = 84
x = 84:28
x = 3
Vậy x = 3
b)\(\frac{2x}{5}=\frac{-24}{10}\)
2x.10=5.(-24)
2x.10= -120
2x = -120 :10
2x= -12
x= -12 : 2
x= -6
Vậy x = -6
a,\(\frac{x}{4}\)=\(\frac{21}{28}\)
\(\Leftrightarrow\)28x=21.4
\(\Leftrightarrow\)28x=84
\(\Leftrightarrow\)x=3
Vậy x=3
b, \(\frac{2x}{5}\)=\(\frac{-24}{10}\)
\(\Leftrightarrow\)2x.10=-24.5
\(\Leftrightarrow\)20x=-120
\(\Leftrightarrow\)x=-6
Vậy x=-6
Chúc bn hk tốt
a/ 5x +y -2x = 28 => 3x +y = 28
x/10 = y/6 = z/21 = 3x /30= y/6 = 3x +y / 36 = 28 /36 = 7/9
=> x= 70/9 ; y = 14/3 ; z= 49/3
b/
x/3 = y/4 => x/15 = y/20 [1]
y/5 = z/7 => y/20 = z/28 [2]
Từ [1] và [2] => x/15 = y/20 = z/28 = 2x /30 = 3y/60 = z/28 = [2x +3y - z] / [30+60-28]= 124 /62 = 2
=> x= 2 .15 = 30 ; y = 2x20 = 40 ; z= 2 . 28= 56
\(\frac{2x}{5}=-\frac{24}{10}\)
=> \(\frac{2x}{5}=-\frac{12}{5}\)
=> 2x = -12
=> x = -12 : 2
=> x = -6
\(\frac{x}{4}=\frac{21}{28}\)
=> \(\frac{x}{4}=\frac{3}{4}\)
=> x = 3
\(\frac{-24}{10}.\frac{x}{4}=\frac{-6}{10}.x=\frac{-3}{5}.x=\frac{21}{28}=\frac{3}{4}\)
\(\Rightarrow x=\frac{3}{4}:\frac{-3}{5}=\frac{-5}{4}\)
Bài 1:
a: =>2x-9=10/91
=>2x=829/91
hay x=829/182
b: =>2x=-7
hay x=-7/2
c: =>-3x=-12
hay x=4
Có \(\frac{x}{4}=\frac{21}{28}\)
\(\Rightarrow x=\frac{21}{28}.4\)
\(\Rightarrow x=3\)
Vậy x=3
b, \(\frac{2x}{5}=\frac{-24}{10}\)
\(\frac{\Rightarrow2x}{5}=-\frac{12}{5}\)
\(\Rightarrow2x=-\frac{12}{5}.5\)
\(\Rightarrow2x=-12\)
\(\Rightarrow x=-12:2\)
\(\Rightarrow x=-6\)
Vậy x=-6
a) \(\frac{x}{4}=\frac{21}{28}\)
\(\Rightarrow\frac{x}{4}=\frac{3}{4}\)
\(\Rightarrow x=3\)
b)\(\frac{2x}{5}=\frac{-24}{10}\)
\(\Rightarrow\frac{2x}{5}=\frac{-12}{5}\)
\(\Rightarrow2x=-12\)
\(\Rightarrow x=-6\)