/x/+/y/>=/x+y/
dấu bằng xảy ra khi nào
K
Khách
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TT
1
15 tháng 1 2022
\(\Leftrightarrow x+y>=2\sqrt{xy}\)
\(\Leftrightarrow\left(\sqrt{x}-\sqrt{y}\right)^2>=0\)(luôn đúng)
Dấu '='xảy ra khi x=y
28 tháng 3 2020
Bài giải
Ta có : ( x- 3 ) 2 \(\ge\)0 <=> x2 - 6.x + 9 \(\ge\) 0 <=> x. ( x - 1 ) \(\ge\)5.x-9 .Tương tự : y. ( y - 1 )\(\ge\) 5.y - 9 .
Từ đó : x . ( x - 1 ) + y . ( y - 1 ) \(\ge\) 5. ( x + y ) -18 \(\ge\) 5. 6 - 18 = 12 . Khi x = y = 3 thì đẳng thức xảy ra => đpcm
JB
0
NC
0
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. Dấu "=" xảy ra khi nào?
NV
Nguyễn Việt Lâm
Giáo viên
5 tháng 5 2021
Cách đơn giản nhất là sử dụng phép biến đổi tương đương:
BĐT đã cho tương đương:
\(\dfrac{x+y}{xy}\ge\dfrac{4}{x+y}\)
\(\Leftrightarrow\left(x+y\right)^2\ge4xy\)
\(\Leftrightarrow x^2-2xy+y^2\ge0\)
\(\Leftrightarrow\left(x-y\right)^2\ge0\) (luôn đúng)
Vậy BĐT đã cho đúng.
Dấu "=" xảy ra khi x=y
