[x+73]:5=20+7,5*4
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Đáp án D
x + 73 : 5 = 20 + 7 , 5 × 4 x + 73 : 5 = 20 + 30 x + 73 : 5 = 50 x + 73 = 250 x = 250 - 73 x = 177
Vậy x=177
Đáp án cần chọn là: D
a, 45,651 x ( 73 + 20 + 7 )
= 45,651 x 100
= 4565,1
b, 35 . 11 . 0,1 + 0,25 . 100 . 0
= 35 . 1,1 + 0
= 38,5
a: \(=2.125+5.375+7.15+6.85+7.5\)
=7,5+14+7,5
=15+14=29
b: \(\Leftrightarrow\left(\dfrac{4}{5}\cdot\dfrac{5}{6}+\dfrac{1}{5}\cdot x\right)\cdot30=60\)
=>(2/3+1/5x)=2
=>1/5x=2-2/3=4/3
=>x=4/3*5=20/3
\(a,\frac{x+15}{x}=\frac{4}{3}\Rightarrow4x=3x+45\Leftrightarrow x=45\)
\(b,\frac{7,5-x}{3,5+x}=\frac{5}{6}\Rightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Rightarrow x=2,5\)
\(c,\frac{x-20}{x-10}=\frac{x+40}{x+70}\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
\(\Leftrightarrow x^2+50x-1400=x^2+30x-400\)
\(\Leftrightarrow20x=1000\)
\(\Rightarrow x=50\)
a. \(\frac{\left(x+15\right)}{x}=\frac{4}{3}\Leftrightarrow4x=3\left(x+15\right)\Leftrightarrow4x=3x+45\Leftrightarrow x=45\)
Vậy x=45
b. \(\frac{7,5-x}{3,5+x}=\frac{5}{6}\Leftrightarrow5\left(3,5+x\right)=6\left(7,5-x\right)\Leftrightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Leftrightarrow x=2,5\)
Vậy x=2,5
c. \(\frac{x+20}{x-10}=\frac{x+40}{x+70}\Leftrightarrow\left(x+40\right)\left(x-10\right)=\left(x+20\right)\left(x+70\right)\)
\(\Leftrightarrow x^2+30x-400=x^2+90x+1400\Leftrightarrow-60x=-30\Leftrightarrow x=-30\)
Vậy x=-30
\(a,\left(x+15\right):x=4:3\)
=>\(1+\dfrac{15}{x}=\dfrac{4}{3}\)
=>\(\dfrac{15}{x}=\dfrac{1}{3}\)
=>\(x=3.15=45\)
Vậy x=45
b)\(\dfrac{7,5-x}{3,5+x}=\dfrac{5}{6}\)
\(6\left(7,5-x\right)=5\left(3,5+x\right)\)
=>\(45-6x=17,5+5x\)
=>\(-11x=-27,5\)
=>\(x=2,5\)
Vậy...
c)\(\dfrac{x-20}{x-10}=\dfrac{x+40}{x+70}\)
=>\(\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
=>\(x^2+50x-140=x^2+30x-40\)
=>\(20x=100\)
=>\(x=50\)
1: Ta có: 7x+6(3-x)=27-20+73
\(\Leftrightarrow7x+18-6x=80\)
\(\Leftrightarrow x=80-18=62\)
Vậy: x=62
2: Ta có: \(6x-5\left(x-7\right)=\left(27-514\right)-486-73\)
\(\Leftrightarrow6x-5x+35=27-514-486-73\)
\(\Leftrightarrow x+35=-1046\)
\(\Leftrightarrow x=-1081\)
Vậy: x=-1081
7,5x . 519 = 5 20 . 511
7,5x . 519 = 531
7,5x =531:519
7,5x=512
Ta có: \(\left(x+73\right):5=20+7.5\cdot4\)
\(\Leftrightarrow\left(x+73\right):5=20+30=50\)
\(\Leftrightarrow x+73=250\)
hay x=177
\(\left(x+73\right)\div5=20+7,5\times4\)
\(\left(x+73\right)\div5=20+30\)
\(\left(x+73\right)\div5=50\)
\(x+73=250\)
\(x=177\)