Bài 2 : Tìm x :
a. 6x - 15 = 19
b. 3x + 2 =20 + ( - 12 )
c. 12x - 33 = 5 . 3 mũ 3
d. ( x+1 ) + ( x+2 ) + ... + ( x+100 ) = 5750
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a)6x-15=19
6x=19+15
6x=34
x=34/6
b)3x+2=20+(-12)
3x+2=8
3x=8-2
3x=6
x=6/3
x=2
c)12x-33=5*33=5*27=135
12x=135+33
12x=168
x=168/12
x=14
d)(x+1)+(x+2)+...+(x+100)=5750
(x+x+....+x)+(1+2+3+....+100)=5750
100x+5050=5750
100x=5750-5050
100x=700
x=700/100
x=7
Bài 4:
a: \(=7xy\left(2-3-4\right)=-35xy\)
b: \(=\left(x-5\right)\left(x+y\right)\)
c: \(=10x\left(x-y\right)+8\left(x-y\right)=2\left(x-y\right)\left(5x+4\right)\)
d: \(=\left(x+y\right)^3-\left(x+y\right)\)
=(x+y)(x+y+1)(x+y-1)
e: =x^2+8x-x-8
=(x+8)(x-1)
f: \(=2x^2-4x+x-2=\left(x-2\right)\left(2x+1\right)\)
g: =-5x^2+15x+x-3
=(x-3)(-5x+1)
h: =x^2-3xy+xy-3y^2
=x(x-3y)+y(x-3y)
=(x-3y)*(x+y)
Bài 4:
a: \(=7xy\left(2-3-4\right)=-35xy\)
b: \(=\left(x-5\right)\left(x+y\right)\)
c: \(=10x\left(x-y\right)+8\left(x-y\right)=2\left(x-y\right)\left(5x+4\right)\)
d: \(=\left(x+y\right)^3-\left(x+y\right)\)
=(x+y)(x+y+1)(x+y-1)
e: =x^2+8x-x-8
=(x+8)(x-1)
f: \(=2x^2-4x+x-2=\left(x-2\right)\left(2x+1\right)\)
g: =-5x^2+15x+x-3
=(x-3)(-5x+1)
h: =x^2-3xy+xy-3y^2
=x(x-3y)+y(x-3y)
=(x-3y)*(x+y)
a) \(60-3.\left(x-2\right)=51\)
\(\Rightarrow3.\left(x-2\right)=60-51=9\)
\(\Rightarrow x-2=9:3=3\)
\(\Rightarrow x=3+2=5\)
b) \(\left(105-x\right):2^5=3^{0+1}=3^1=3\)
\(\Rightarrow\left(105-x\right):32=3\)
\(\Rightarrow105-x=3.32=96\)
\(\Rightarrow x=105-96=9\)
c) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5=10\)
1a) -3x2(2x3 - 2x + 1/3) = -6x5 + 6x3 - x2
b) (x4 + 2x3 - 2/3).(-3x4) = -3x8 - 6x7 + 2x4
c) (x + 3)(x - 4) = x2 - 4x + 3x - 12 = x2 - x - 12
d)(x - 4)(x2 + 4x + 16) = (x - 4)(x2 + 4x + 42) = x3 - 64
e) 4(x - 1/2)(x + 1/2)(4x2 + 1) =4(x2 - 1/4)(4x2 + 1) = 4(4x4 + x2 - x2 - 1/4) = 4(4x4 - 1/4) = 16x4 - 1
B2. a) (2 - x)(x2 + 2x + 4) + x(x - 3)(x + 4) - x2 + 24 = 0
=> 8 - x3 + x(x2 + 4x - 3x - 12) - x2 + 24 = 0
=> 8 - x3 + x3 + x2 - 12x - x2 + 24 = 0
=> -12x + 32 = 0
=> -12x = -32
=> x = -32 : (-12) = 8/3
b) (x/2 + 3)(5 - 6x) + (12x - 2)(x/4 + 3) = 0
=> 5x/2 - 3x2 + 15 - 18x + 3x2 + 36x - x/2 - 6 = 0
=> 20x + 9 = 0
=> 20x = -9
=> x = -9/20
a) 6x = 19 + 15 = 34
=> x = 34 : 6 = 17/3
b) 3x + 2 = 8
=> 3x = 8 - 2 = 6
=> x = 6 : 3 = 2
c) 12x - 33 = 135
=> 12x = 135 + 33 = 168
=> x = 168 : 12 = 14
d) 100x + \(\frac{100.101}{2}\) = 5750
<=> 100x + 5050 = 5750
=> 100x = 5750 - 5050 = 700
=> x = 700 : 100 = 7
Bài 2:Tìm x
a.6x-15=19 b. 3x+2=20+(-12)
6x=19+15 3x+2=8
6x=34 3x=6
x=34:6 x=6:3
x=17/3 x=2
Vậy x=17/3 Vậy x=2
c) 12x - 33=5.3^3 d) ( x+1 ) + ( x+2 ) + ... + ( x+100 ) = 5750
12x-33=135 Vì cứ 1 số hạng lại có 1x
12x=135-33 Vậy từ 1 đến 100 có số số hạng là:
12x=102 (100-1):1+1=100(số)
x=102:12 Tổng dãy số là:
x=17/2 (100+1)x100:2=5050
Vậy x=17/2 Do đó có 100x ta có:
( x+1 ) + ( x+2 ) + ... + ( x+100 ) = 5750
(x+x+...+x)+(1+2+...+100)=5750
100x+5050=5750
100x=700
x=7
Vậy x=7