rút gọn biểu thức: a) (2x + y)^3 - (2x - y)^3 b) (5 - 3x)^3 - (5 + 3x)^3
c) (x +3) . (x^2 - 2x + 9) - (54 + x^3)
d) (2x + y) . (4x^2 - 2xy +y^2) - (2xy) . (4x^2 + 2xy + y^2)
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a) (x+3)(x^2-3x+9)-(54+x^3)
= x^3- 3x^2+9x+3x^2-9x+27-54-x63
= -27
b) (2x + y)(4x^2 – 2xy + y^2) – (2x – y)(4x^2+ 2xy + y^2)
= (2x + y)[(2x)^2 – 2x.y + y^2] – (2x – y)[(2x)^2 + 2x.y + y^2]
= [(2x)3^3+ y^3] – [(2x)^3 – y^3]
= (2x)^3 + y^3 – (2x)^3 + y^3
= 2y^3
a)(x+3)(X^2-3x+9)-(54+x^3)
= \(x^3\)+ \(3^3 \) - 54 -\(x^3\)
= 27- 54
= -27
b)(2x+y)(4x^2-2xy+y^2)-(2x-y)(4x^2+2xy+y^2)
= \((2x)^3\) + \(y^3\) - [\((2x)^3\) - \(y^3\) ]
= \(8x^3\) + \(y^3\) - \(8x^3\) + \(y^3\)
= \(2y^3\)
b) \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(=\left(2x+y\right)\left(4x^2-2xy+y^2\right)+\left(2x+y\right)\left(4x^2+2xy+y^2\right)\)
\(=\left(2x+y\right)\left(4x^2-2xy+y^2+4x^2+2xy+y^2\right)\)
\(=\left(2x+y\right)\left(8x^2+2y^2\right)\)
\(=\left(2x+y\right)\left(4x+y\right).2xy\)
a) (2x-y)(2x+y)-(2x+y)^2
= 4x2-y2-(4x2+4xy+y2)
= 4x2-y2-4x2-4xy-y2
= -4xy
b) (x-3)(x^2+3x+9)-(5-x)^2
= (x3-27)-(25-10x+x2)
= x3-27-25+10x-x2
= x3-x2+10x-52
c) (2x+y)(4x^2-2xy+y^2)-(2x+y)^3
= (2x)3+y3- ((2x)3+3.4x2.y+3.y2.2x+y3)
= 8x3+y3-(8x3+12x2y+6xy2+y3)
= 8x3+y3-(8x3+12x2y+6xy2+y3)
= 8x3+y3-8x3-12x2y-6xy2-y3
=-12x2y-6xy2
d) (3x-5)^2-(3x+5)^2
= (3x-5-3x-5)(3x-5+3x+5)
= -10.6x
= -60x
1: Ta có: \(\left(x+3\right)\left(x^2-3x+9\right)-\left(x^3+54\right)\)
\(=x^3+27-x^3-54\)
=-27
2: Ta có: \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(=8x^3+y^3-8x^3+y^3\)
\(=2y^3\)
\(1,=x^3+270-x^3-54=-27\\ 2,=8x^3+y^3-8x^3+y^3=2y^3\\ 3,=x^3-3x^2+3x-1-x^3-8+3x^2-48=3x-57\\ 4,=x^3-x-x^3-1=-x-1\\ 5,=8x^3-5\left(8x^3+1\right)=-32x^3-5\\ 6,=27+x^3-27=x^3\\ 7,làm.ở.câu.3\\ 8,=x^3-6x^2+12x-8+6x^2-12x+6-x^3-1+3x\\ =3x-3\)
a) (x+y+x_y).(x+y_x+y)
b ) (( x + y )+(x _ y))2
d ) 8x3 + y3 _ 8x3 + y3 =2y3
Bài 1:
\(a,\left(2x-y\right)\left(2x+y\right)-\left(2x+y\right)^2\)
\(=4x^2-y^2-4x^2-4xy+y^2\)
\(=-4xy\)
\(b,\left(x-3\right)\left(x^2+3x+9\right)-\left(5-x\right)^2\)
\(=x^3-27-25+10x-x^2\)
\(=x^3-x^2+10x-52\)
\(c,\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x+y\right)^3\)
\(=8x^3+y^3-4x^2-4xy-y^2\)
\(d,\left(3x-5\right)^2-\left(3x+5\right)^2\)
\(=\left(3x-5-3x-5\right)\left(3x-5+3x+5\right)\)
\(=-10.6x=-60x\)
Trả lời:
a, ( 2x + y )3 - ( 2x - y )3
= ( 2x )3 + 3.( 2x )2.y + 3.2x.y2 + y3 - [ ( 2x )3 - 3.( 2x )2.y + 3.2x.y2 - y3 ]
= 8x3 + 12x2y + 6xy2 + y3 - ( 8x3 - 12x2y + 6xy2 - y3 )
= 8x3 + 12x2y + 6xy2 + y3 - 8x3 + 12x2y - 6xy2 + y3
= 24x2y + 2y3
b, ( 5 - 3x )3 - ( 5 + 3x )3
= 53 - 3.52.3x + 3.5.( 3x )2 - ( 3x )3 - [ 53 + 3.52.3x + 3.5.( 3x )2 + ( 3x )3 ]
= 125 - 225x + 135x2 - 27x3 - ( 125 + 225x + 135x2 + 27x3 )
= 125 - 225x + 135x2 - 27x3 - 125 - 225x - 135x2 - 27x3
= - 54x3- 450x
c, ( x + 3 ) ( x2 - 2x + 9 ) - ( 54 + x3 )
= x3 - 2x2 + 9x + 3x2 - 6x + 27 - 54 - x3
= x2 + 3x - 27
d, ( 2x + y ) ( 4x2 - 2xy + y2 ) - 2xy ( 4x2 + 2xy + y2 )
= ( 2x )3 + y3 - 8x3y - 4x2y2 - 2xy3
= 8x3 + y3 - 8x3y - 4x2y2 - 2xy3