Rút gọn
a) \(\frac{16^5.21^6.45^3.30^2}{18^5.24^6.48^3.36^2}\)
b) \(\frac{6^9.30^6.8^7.14^8}{9^7.24^6.10^7.7^9}\)
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a))\(\frac{2^3.3^3.3^3.3^4.5^4.5^4.3^7.2^7.2^7.2^7.2^6}{2^5.2^5.3^5.2^6.2^6.3^6.3^6.3^4.5^4}=\frac{5^4.2^7}{3^4}=\frac{625.128}{81}=\frac{80000}{81}\)
\(\frac{18^3.75^4.24^7.2^6}{12^5.36^6.15^4}=\frac{2^3.3^6.3^4.5^8.2^{21}.3^7.2^6}{2^{10}.3^5.2^{12}.3^{12}.3^4.5^4}=\frac{2^{30}.3^{17}.5^8}{2^{22}.3^{21}.5^4}=\frac{2^8.5^4}{3^4}\)
mình làm đúng đó không tin thì bấm máy tính thử đi phạm thủy linh làm sai rồi
cho mình đúng hen
f) \(\frac{25^2.20^4}{5^{10}.4^5}=\frac{\left(5^2\right)^2.\left(4.5\right)^4}{5^{10}.4^5}=\frac{5^4.5^4.4^4}{5^{10}.4^5}=\frac{5^8.4^4}{5^{10}.4^5}=\frac{1}{5^2.4}=\frac{1}{100}\)
g) \(\frac{16^{12}.8}{32^5.64^4}=\frac{\left(2^4\right)^{12}.2^3}{\left(2^5\right)^5.\left(2^6\right)^4}=\frac{2^{48}.2^3}{2^{25}.2^{24}}=\frac{2^{51}}{2^{49}}=2^2=4\)
h) \(\frac{2^{18}.9^4}{6^6.8^4}=\frac{2^{18}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^4}=\frac{2^{18}.3^8}{2^6.3^6.2^{12}}=\frac{2^{18}.3^8}{2^{18}.3^6}=3^2=9\)
b) \(\frac{36^7}{2^{15}.27^5}=\frac{\left(2^2.3^2\right)^7}{2^{15}.\left(3^3\right)^5}=\frac{2^{14}.3^{14}}{2^{15}.3^{15}}=\frac{1.1}{2.3}=\frac{1}{6}\)
h) \(\frac{2^{18}.9^4}{6^6.8^4}=\frac{2^{18}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^4}=\frac{2^{18}.3^8}{2^6.3^6.2^{12}}=\frac{2^{18}.3^8}{2^{18}.3^6}=\frac{1.3^2}{1.1}=9\)
o) \(\frac{3^3+3.6^2+6^3}{13}=\frac{3^3+6^2\left(3+6\right)}{13}=\frac{3^3+6^2.3^2}{13}\)
\(=\frac{3^2\left(3+6^2\right)}{13}=\frac{9.3.13}{13}=\frac{9.3.1}{1}=27\)
a) `(-63)/72 = (-63:9)/(72:9)=(-7)/8`
b) `20/(-140) = (20:20)/(-140:20) = 1/(-7)=(-1)/7`
c) `(3.10)/(5.24) =(3.2.5)/(5.2 .3.4)=1/4`
d) `(6.5-6.2)/(6+3)=18/9=2`
\(\frac{2^{15}.9^4}{6^6.8^3}\)
\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}\)
\(=\frac{2^{15}.3^8}{2^6.3^6.2^9}\)
\(=\frac{2^{15}.3^8}{2^{15}.3^6}\)
\(=3^2\)
\(=9\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(3.2\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{3^6.2^6.2^9}=\frac{2^{15}.3^8}{3^6.2^{15}}=\frac{3^8}{3^6}=3^2=9\)
\(A=\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{48.50}.\)
\(=\frac{1}{2}.\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}....+\frac{2}{48.50}\right)\)
\(=\frac{1}{2}.\left(\frac{4-2}{2.4}+\frac{6-4}{4.6}+\frac{8-6}{6.8}+...+\frac{50-48}{48.50}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+.....+\frac{1}{48}-\frac{1}{50}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{50}\right)\)
\(=\frac{1}{2}.\frac{12}{25}=\frac{6}{25}\)
\(B=\frac{3}{1.4}+\frac{3}{4.7}+....+\frac{3}{97.100}\)
\(=\frac{4-1}{1.4}+\frac{7-4}{4.7}+....+\frac{100-97}{97.100}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.....+\frac{1}{97}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
\(C=\frac{8}{7.14}+\frac{8}{14.21}+....+\frac{8}{91.98}\)
\(=\frac{7}{8}.\left(\frac{7}{7.14}+\frac{7}{14.21}+...+\frac{7}{91.98}\right)\)
\(=\frac{7}{8}.\left(\frac{1}{7}-\frac{1}{14}+\frac{1}{14}-\frac{1}{21}+.....+\frac{1}{91}-\frac{1}{98}\right)\)
\(=\frac{7}{8}.\left(\frac{1}{7}-\frac{1}{98}\right)\)
\(=\frac{7}{8}.\frac{13}{98}=\frac{13}{112}\)
a)
\(\frac{16^5.21^6.45^3.30^2}{18^5.24^6.48^3.36^2}=\frac{2^{20}.3^6.7^6.5^3.3^6.3^2.2^2.5^2}{2^5.3^{10}.3^6.2^{18}.3^3.2^{12}.2^4.3^4}=\frac{2^{22}.3^{14}.7^6.5^5}{2^{39}.3^{23}}=\frac{7^6.5^5}{2^{17}.3^{11}}\)
b)
\(\frac{6^9.30^6.8^7.14^8}{9^7.24^6.10^7.7^9}=\frac{3^9.2^9.3^6.10^6.2^{21}.7^8.2^8}{3^{14}.3^6.2^{18}.10^7.7^9.}=\frac{3^{15}.2^{38}}{3^{20}.2^{18}.10.7}=\frac{2^{20}}{3^5.2.5.7}=\frac{2^{19}}{3^5.35}\)