phân tích thành nhân tử : x4+2015x2+2014x+2015
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\(x^4+2015x^2+2014x+2015\)
\(=\left(x^4-x\right)+2015x^2+2015x+2015\)
\(=x\left(x^3-1\right)+2015\left(x^2+x+1\right)\)
\(=x\left(x-1\right)\left(x^2+x+1\right)+2015\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+2015\right)\)
Sửa đề: 2016x^2
x^4+2016x^2+2015x+2016
=x^4+x^3+x^2-x^3-x^2-x+2016x^2+2016x+2016
=(x^2+x+1)(x^2-x+2016)
ta có:
x^4+2014x^2+2013x+2014 = x^4+2013x^2+x^2+2013x+2013+1
=(x^4+x^2+1)+2013(x^2+x+1)
=(x^2+1)^2-x^2+2013(x^2+x+1)
=(x^2-x+1)(x^2+x+1)+2013(x^2+x+1)
=(x^2+x+1)(x^2+x+2014)
x4+2014x2+2013x+2014=(x4-x)+(2014x2+2014x+2014)
=x(x-1)(x2+x+1)+2014(x2+x+1)
=(x^2+x+1)(x2-x+2014)
x^4+2014x^2+2013x+2014 = x^4+2013x^2+x^2+2013x+2013+1
=(x^4+x^2+1)+2013(x^2+x+1)
=(x^2+1)^2-x^2+2013(x^2+x+1)
=(x^2-x+1)(x^2+x+1)+2013(x^2+x+1)
=(x^2+x+1)(x^2+x+2014)
a: \(=x^2\left(x-y\right)+2014\left(x-y\right)=\left(x-y\right)\left(x^2+2014\right)\)
x4+2015x2+2014x+2015
=x4-x+2015x2+2015x+2015
=x.(x3-1)+2015.(x2+x+1)
=x.(x-1)(x2+x+1)+2015.(x2+x+1)
=(x2+x+1)(x2-x+2015)
\(x^4+2015x^2+2014x+2015=\left(x^4+x^3+x^2\right)-\left(x^3+x^2+x\right)+\left(2015x^2+2015x+2015\right)\)
\(=x^2\left(x^2+x+1\right)-x\left(x^2+x+1\right)+2015\left(x^2+x+1\right)=\left(x^2+x+1\right)\left(x^2-x+2015\right)\)