Giúp mình với √12-√75+√27
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a) 27 . 75 + 25 .27 - 150 = 27 . (75 + 25) - 150
= 270 . 100 - 150
= 27 000 - 150
= 26 850
b) 3.52 - 16 : 22 = 12,25 - 16 : 4
= 12,25 - 4
= 8,25
c) 20 - [30 - (5 - 1)2 ] = 20 - [30 - 42 ]
= 20 - 30 - 16
= (-10) - 16
= -26
d) 60 : {[(12 - 3) . 2] + 2} = 60 : {[9 . 2] + 2}
= 60 : {18 + 2}
= 60 : 20
= 3
+) Ta có: \(2\sqrt{75}-4\sqrt{27}+3\sqrt{12}\)
\(=2\sqrt{25}.\sqrt{3}-4\sqrt{9}.\sqrt{3}+3\sqrt{4}.\sqrt{3}\)
\(=10.\sqrt{3}-12.\sqrt{3}+6.\sqrt{3}\)
\(=4\sqrt{3}\approx6,9282\)
+) Ta có:\(\sqrt{x+6\sqrt{x-9}}\)
\(=\sqrt{x-9+6\sqrt{x-9}+9}\)
\(=\sqrt{\left(\sqrt{x-9}-3\right)^2}\)
\(=\left|\sqrt{x-9}-3\right|\)
\(\frac{2}{\sqrt{5}+\sqrt{3}}+\frac{1}{2-\sqrt{3}}=\frac{2\left(\sqrt{5}-\sqrt{3}\right)}{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}+\frac{2+\sqrt{3}}{\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)}\)
\(=\frac{2\left(\sqrt{5}-\sqrt{3}\right)}{5-3}+\frac{2+\sqrt{3}}{4-3}=\sqrt{5}-\sqrt{3}+2+\sqrt{3}=\sqrt{5}+2\)
(77 + 22 - 65) - (67 + 12 - 75)
= 77 + 22 - 65 - 67 - 12 + 75
= (77 - 67) + (22 - 12) + (75 - 65)
= 10 + 10 + 10
= 30
5 . 12 - 15/12 - 27 = 60 - 15/12 - 27
= 60 - 27 - 15/12
= 33 - 15/12
= 127/4
d: \(\dfrac{1}{27}:\left(-\dfrac{1}{3}\right)^2+75\%\cdot\left(-\dfrac{2^2}{3}\right)\)
\(=\dfrac{1}{27}:\dfrac{1}{9}+\dfrac{3}{4}\cdot\dfrac{-4}{3}\)
\(=\dfrac{1}{3}-1\)
\(=-\dfrac{2}{3}\)
27.((-75)-25) -150
=27.(-100)-150
=-2850
194.12+(6.2).437+(3.4).369
12.(194+437+369)
=12.1000=12000
a) ( - 78 ) . ( 1 + 187 ) + 187 . 78
= ( - 78 ) + ( - 78 ) . 187 + 187 . 78
= ( - 78 ) + 187 . [ ( - 78 ) + 78 ]
= ( - 78 ) + 187 . 0
= ( - 78 ) + 0
= ( - 78 )
b) ( - 39 ) . 15 - 36 . 39 - 49 . ( - 39 )
= ( - 39 ) . 15 + 36 . ( - 39 ) - 49 . ( - 39 )
= ( - 39 ) . ( 15 + 36 - 49 )
= ( - 39 ) . 2
= - 78
a) (-78).(1+187) + 187.78 = -78 - 78.187 +187.78 = -78
b) (-39).15 - 36.39 - 49.(-39)
= -39.15 - 36.39 + 49.39
=39.(-15-36+49)
= 39.(-2)
= - 78
Tích mk nha !!!!~~
`sqrt{12}-sqrt{75}+sqrt{27}`
`=sqrt{4.3}-sqrt{25.3}+sqrt{9.3}`
`=2sqrt3-5sqrt3+3sqrt3=0`
Ta có : \(\sqrt{12}-\sqrt{75}+\sqrt{27}=2\sqrt{3}-5\sqrt{3}+3\sqrt{3}=0\)