Tính A=1/3.8 + 1/8.13 + 1/13/8 + ... + 1/33.38 B=1/3.10 + 1/10.17 + 1/17.24 + 1/24.31 + 1/31.38
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A=1/3.8+1/8.13+1/13.18+...+1/33.38
5A=5/3.8+5/8.13+5/13.18+...+5/33.38
5A=1/3-1/8+1/8-1/13+1/13-1/18+...+1/33-1/38
5A=1/3-1/38
5A=38/114-3/114
5A=35/114
A=35/114:5
A=7/114
B=1/3.10+1/10.17+1/17.24+1/24.31+1/31.38
7B=7/3.10+7/10.17+7/17.24+7/24.31+7/31.38
7B=1/3-1/10+1/0-1/17+1/17-1/24+1/24-1/31+1/31-1/38
7B=1/3-1/38
7B=38/114-3/114
7B=35/114
B=35/114:7
B=5/114
Ta có: *)A.5=5(1/3.8+1/8.13+...+1/33.38)
=5/3.8+5/8.13+...+5/33.38
=1/3-1/8+1/8-1/13+...+1/33-1/38
=1/3-1/38
=> A=(1/3-1/38).1/5
*)7B=7/3.10+7/10.17+7/17.24+...+7/31.38
=1/3-1/10+1/10-1/17+...+1/31-1/38
=1/3-1/38
=>B=(1/3-1/38).1/7
Do đó a/b=(1/5)/(1/7)=7/5
k mk nha!
Ta có:
P=\(\frac{1}{3.10}\)+\(\frac{1}{10.17}\)+\(\frac{1}{17.24}\)+......+\(\frac{1}{73.80}\)-\(\frac{1}{2.9}\)-\(\frac{1}{9.16}\)-\(\frac{1}{16.23}\)-\(\frac{1}{23.30}\))
P=\(\frac{1}{7}\)\(\times\)(\(\frac{7}{3.10}\)+\(\frac{7}{10.17}\)+\(\frac{7}{17.24}\)+......\(\frac{7}{73.80}\)-\(\frac{7}{2.9}\)-\(\frac{7}{9.16}\)-\(\frac{7}{16.23}\)-\(\frac{7}{23.30}\))
P=\(\frac{1}{7}\)\(\times\)(\(\frac{1}{3}\)-\(\frac{1}{10}\)+\(\frac{1}{10}\)-\(\frac{1}{17}\)+.....+\(\frac{1}{73}\)-\(\frac{1}{80}\)-\(\frac{1}{2}\)-\(\frac{1}{9}\)-......-\(\frac{1}{23}\)-\(\frac{1}{30}\))
P=\(\frac{1}{7}\)\(\times\)(\(\frac{1}{3}\)-\(\frac{1}{80}\))-\(\frac{1}{7}\)(\(\frac{1}{2}\)-\(\frac{1}{30}\))
P=\(\frac{1}{7}\)\(\times\)(\(\frac{1}{3}\)-\(\frac{1}{80}\)-\(\frac{1}{2}\)+\(\frac{1}{30}\))
P=\(\frac{-7}{336}\)
Bài này mk ko tính máy tính nên ko chắc đâu
taị mk ko tính máy tính lên sai.
bn thông cảm nha. thường ngày hay dùng máy tính quá nên tính sai thì bn thông cảm
Đặt biểu thức cần tính là A, ta có:
A=\(\dfrac{1}{7}\left(\dfrac{7}{3.10}+\dfrac{7}{10.17}+...+\dfrac{7}{73.80}\right)\)
Làm tg tự với những cái khác là ok
a)\(2-\frac{1}{10.9}-\frac{1}{9.8}-\frac{1}{8.7}-.....-\frac{1}{3.2}-\frac{1}{2.1}=2-\left(\frac{1}{10.9}+\frac{1}{9.8}+\frac{1}{8.7}+....+\frac{1}{3.2}+\frac{1}{2.1}\right)\)
\(=2-\left(\frac{1}{10}-\frac{1}{9}+\frac{1}{9}-\frac{1}{8}+\frac{1}{8}-\frac{1}{7}+....+\frac{1}{3}-\frac{1}{2}+\frac{1}{2}-1\right)\)
\(=2-\left(\frac{1}{10}-1\right)=2-\frac{-9}{10}=\frac{29}{10}\)
b)\(\frac{5}{2.8}+\frac{5}{8.14}+\frac{5}{14.20}+\frac{5}{20.26}+\frac{5}{26.32}=5\left(\frac{1}{2.8}+\frac{1}{8.14}+\frac{1}{14.20}+\frac{1}{20.26}+\frac{1}{26.32}\right)\)
\(=5\left[\frac{1}{6}\left(\frac{1}{2}-\frac{1}{8}+\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\right]\)
\(=5\left[\frac{1}{6}\left(\frac{1}{2}-\frac{1}{32}\right)\right]=5\left(\frac{1}{6}.\frac{15}{32}\right)=5.\frac{5}{64}=\frac{25}{64}\)
5A = 5/3.8 + 5/8.13 + 5/13.18 + ... + 5/33.38
= 1/3 - 1/8 + 1/8 - 1/13 + ... + 1/33 - 1/38
= 1/3 - 1/38
5A = 35/114
=> A = 35/114 : 5 = 7/144
7B = 7/3.10 + 7/10.17 + ... + 7/31.38
= 1/3 - 1/10 + 1/10- 1/17 + .. + 1/31 - 1/38
= 1/3 - 1/38
B = 35/144 : 7 = 5/144
VẬy A> B
tính tổng đó