1
tìm X
X/2 + X/3 + X/4 =180
1/X x 2 + 2/ X x3 + 3/ X x 4=120
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a) 232 - (3x + 2).5 = 23.52
232 - (3x + 2).5 = 8.25
232 - 5.(3x + 2) = 200
-5.(3x + 2) = 200 - 232
-5.(3x + 2) = -32
3x + 2 = (-32) : (-5)
3x + 2 = 32/5
3x = 32/5 - 2
3x = 22/5
x = 22/5 : 3
x = 22/15
\(a)232-\left(3x+2\right).5=2^3.5^2\)
\(\Leftrightarrow232-\left(3x+2\right).5=200\)
\(\Leftrightarrow\left(3x+2\right).5=32\)
\(\Leftrightarrow3x+2=6.4\)
\(\Leftrightarrow3x=4.4\)
\(\Leftrightarrow\frac{22}{15}\)
\(b)3.5^x-10^0=74\)
\(\Leftrightarrow3.5^x=75\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
\(\Leftrightarrow x=2\)
\(c)4^{2x+4}=64\)
\(\Leftrightarrow4^{2x+4}=4^3\)
\(\Leftrightarrow2x+4=3\)
\(\Leftrightarrow x=-\frac{1}{2}\)
\(d)5^{x-1}+5^x=100\)
\(\Leftrightarrow5^x.\frac{1}{5}+5^x=100\)
\(\Leftrightarrow5^x\left(\frac{1}{5}+1\right)=100\)
\(\Leftrightarrow5^x=\frac{250}{3}\)
Chưa nghĩ ra. Các câu khác tương tự như các câu trên.
Bài 1:
a) \(3x^2\left(2x^3-x+5\right)-6x^5-3x^3+10x^2\)
\(=6x^5-3x^3+10x^2-6x^5-3x^3+10x^2\)
\(=10x^2+10x^2\)
\(=20x^2\)
b) \(-2x\left(x^3-3x^2-x+11\right)-2x^4+3x^3+2x^2-22x\)
\(=-2x^4+6x^3+2x^2-22x-2x^4+3x^3+2x^2-22x\)
\(=-4x^4+9x^3+4x^2-44x\)
\(\left(x-2\right)\left(x^2+2x+4\right)+3x-4=\left(x+2\right)\left(x^2-2x+4\right)-x+1\)
\(\Rightarrow\left(x^3-8\right)+3x-4=\left(x^3+8\right)-x+1\)
\(\Rightarrow x^3-8+3x-4=x^3+8-x+1\)
\(\Rightarrow x^3-x^3+3x+x=8+8+4+1\)
\(\Rightarrow4x=21\)
\(\Rightarrow x=\dfrac{21}{5}\)
Bài 2:
Sửa đề: \(x^3-3x^2-10x=0\)
\(\Leftrightarrow x\left(x^2-3x-10\right)=0\)
\(\Leftrightarrow x\left(x-5\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\\x=-2\end{matrix}\right.\)
a) (x-2)3+6(x+1)2-x3+12=0
\(\Rightarrow\)x3-6x2+12x-8+6(x2+2x+1)-x3+12=0
\(\Rightarrow\)x3-6x2+12x-8+6x2+12x+6-x3+12=0
\(\Rightarrow\)24x+10=0
\(\Rightarrow\)24x=-10
\(\Rightarrow\)x=\(\dfrac{-10}{24}=\dfrac{-5}{12}\)
b)(x-5)(x+5)-(x+3)2+3(x-2)2=(x+1)2-(x-4)(x+4)+3x2
\(\Rightarrow\)x2-25-(x2+6x+9)+3(x2-4x+4)=x2+2x+1-(x2-16)+3x2
\(\Rightarrow\)x2-25-x2-6x-9+3x2-12x+12=x2+2x+1-x2+16+3x2
\(\Rightarrow\)3x2-18x-22=3x2+2x+17
\(\Rightarrow\)3x2-18x-22-3x2-2x-17=0
\(\Rightarrow\)-20x-39=0
\(\Rightarrow\)-20x=39
\(\Rightarrow\)x=\(-\dfrac{39}{20}\)
a, x+15=20-4x
=> x + 4x = 20 - 15
=> 5x = 5
=> x = 5 : 5
=> x = 1
b, 17-x=7-6x
=> -x + 6x = 7 - 17
=> 5x = - 10
=> x = -10 : 5
=> x = -2
c, 4.(x-5)-3.(x+7)= -19
=> 4x - 4.5 - 3.x + 3.7 = -19
=> 4x - 20 - 3x + 21 = -19
=> (4x-3x) + (21-20) = -19
=> 1x + 1 = -19
=> x = -19 - 1
=> x = -18
d, -7.(5-x)-2.(x-10)=15
=> -7x - (-7).5 - 2x - 2.10 = 15
=> -7x - (-35) - 2x - 20 = 15
=> -7x + 35 - 2x - 20 = 15
=> -7x+2x + (35-20) = 15
=> -5x + 15 = 15
=> -5x = 15 - 15
=> -5x = 0
=> x = 0 : (-5)
=> x = 0
e, -5.(2-x)+4.(x-3) = 10.x-15
=> -5x - (-5).2 + 4x - 4.3 = 10x - 15
=> -5x - (-10) + 4x - 12 = 10x - 15
=> -5x + 10 + 4x - 12 = 10x - 15
=> (-5x+4x) - (12-10) = 10x - 15
=> -1x - 2 = 10x - 15
=> -1x - 10x = -15 + 2
=> -11x = -13
=> x = \(\frac{-13}{-11}\)
a/ \(\frac{x}{2}+\frac{x}{3}+\frac{x}{4}=180\)
\(\Leftrightarrow x\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)=180\)
\(\Leftrightarrow\frac{13}{12}x=180\)
\(\Leftrightarrow x=\frac{2160}{13}\)
b/ \(\frac{1}{x.2}+\frac{2}{x.3}+\frac{3}{x.4}=120\)
\(\Leftrightarrow\frac{1}{x}\left(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}\right)=120\)
\(\Leftrightarrow\frac{1}{x}.\frac{23}{12}=120\)
\(\Leftrightarrow\frac{1}{x}=\frac{1440}{23}\)
\(\Leftrightarrow x=\frac{23}{1440}\)
ý b của mik là 23/12