45.(7373/3030+7373/4242+7373/5656+7373/7272)
tính nhanh
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\(45\left(\frac{7373}{3030}+\frac{7373}{4242}+\frac{7373}{5656}+\frac{7373}{7272}\right)\)
\(=45\left(\frac{73.101}{30.101}+\frac{73.101}{42.101}+\frac{73.101}{56.101}+\frac{73.101}{72.101}\right)\)
\(=45\left(\frac{73}{30}+\frac{73}{42}+\frac{73}{56}+\frac{73}{42}\right)\)
\(=45.73\left(\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)\)
\(=45.73\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)\)
\(=45.73\left(\frac{1}{5}-\frac{1}{9}\right)\)
\(=45.73\left(\frac{9}{45}-\frac{5}{45}\right)\)
\(=45.73.\frac{4}{45}\)
\(=292\)
\(B=45.\left(\frac{7373}{3030}+\frac{7373}{4242}+\frac{7373}{5656}+\frac{7373}{9090}\right)\)
\(B=45.\left(\frac{73}{30}+\frac{73}{42}+\frac{73}{56}+\frac{73}{90}\right)\)
\(B=45.73.\left(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{90}\right)\)
\(B=3285.\left(\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{9.10}\right)\)
\(B=3285.\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{90}\right)\)
\(B=3285.\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{90}\right)\)
\(B=3285.\frac{31}{360}=\frac{2263}{8}\)
Ta có :
1313/9191
= (13.101)/(91.101)
= 13/91 . 101/101
= 13/91
= 13/(7.13)
= 1/7.13/13
= 1/7
Mà : 1111/7373
= (11.101)/(73.101)
= 11/73 . 101/101
= 11/73
Ta có : 1/7 = 11/(7.11) = 11/77 < 11/73
hay : 1313/9191 < 1111/7373
2323/202+2323/606+2323/1212+2323/2020+2323/3030+2323/4242+2323/5656+2323/7272+2323/9090.=
\(\frac{23\times101}{2\times101}+\frac{23\times101}{6\times101}+\frac{23\times101}{12\times101}+....+\frac{23\times101}{72\times101}+\frac{23\times101}{90\times101} \)
=\(\frac{23}{2}+\frac{23}{6}+..........+\frac{23}{72}+\frac{23}{90}\)
=\(23\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}+.....+\frac{1}{9\times10}\right)\)
=\(23\times\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}_{ }\right)\)
=\(23\left(1-\frac{1}{10}\right)_{ }\)
=\(23\times\frac{9}{10}\)
==\(\frac{207}{10}\)
chúc học giỏi nha bn
Ta có: \(-\frac{5151}{7373}=\frac{-51.101}{73.101}=-\frac{51}{73}\)
Vậy \(-\frac{51}{73}=-\frac{5151}{7373}\).
Ta có:-51/73=(-51)x101/73x101=-5151/7373
Do đó: hai phân số -51/73 = -5151/7373
tick nha
Gọi hai số cần tìm là a; b (a,b thuộc Z )
Vì tích của hai số bằng -7373
=> ab = -7373
=>a = -7373/b
Mà tổng là 28
=> a+b=28
=>-7373/b+b=28
=>b=101
=> a = -73
vậy hai số nguyên cần tìm là -73 ; 101
hok tốt
DẦU TIÊN PHÂN TÍCH -7373 RA THỪA SO NGUYÊN TỐ
-7373= -73.101
-73+101=28
VẬY HAI SỐ ĐÓ LÀ: -73;101
K CHO MÌNH NHÉ!
b)
ta có : \(\frac{1313}{9191}=\frac{13}{91}=\frac{1}{7}\)
\(\frac{1111}{7373}=\frac{11}{73}>\frac{11}{77}\)
Mà \(\frac{11}{77}=\frac{1}{7}\)
\(\Rightarrow\frac{11}{73}>\frac{1}{7}\)
Vậy \(\frac{1313}{9191}< \frac{1111}{7373}\)
1-21/52=31/52 1-213/523=310/523 ta có 31/52=310/520
vì 310/520<310/523 nên 21/52 < 213/523
phần còn lại như bạn bên trên nha! chọn mk nhé!
\(\frac{1313}{9191}=\frac{1313:1313}{9191:1313}=\frac{1}{7}=\frac{73}{511}\)
\(\frac{1111}{7373}=\frac{1111:101}{7373:101}=\frac{11}{73}=\frac{77}{511}\)
Vì \(\frac{73}{511}< \frac{77}{511}\) nên \(\frac{1313}{9191}< \frac{1111}{7373}\).
\(\frac{1313}{9191}=\frac{13}{91}=\frac{1}{7}=0.14...\)
\(\frac{1111}{7373}=\frac{11}{73}=0,15.....\)
MÀ 0, 14 <0, 15
=> \(\frac{1313}{9191}< \frac{1111}{7373}\)
\(45.\left(\frac{7373}{3030}+\frac{7373}{4242}+\frac{7373}{5656}+\frac{7373}{7272}\right)\)
\(=45.\left(\frac{101.73}{101.30}+\frac{101.73}{101.42}+\frac{101.73}{101.56}+\frac{101.73}{101.72}\right)\)
\(=45.\left(\frac{73}{30}+\frac{73}{42}+\frac{73}{56}+\frac{73}{72}\right)\)
\(=45.\left(\frac{73}{5.6}+\frac{73}{6.7}+\frac{73}{7.8}+\frac{73}{8.9}\right)\)
\(=45.73.\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)\)
\(=45.73.\left(\frac{1}{5}-\frac{1}{9}\right)\)
\(=45.73.\frac{4}{45}\)
\(=73.4\)
\(=292\)