Các bạn giải giúp mình câu này với:
\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)
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\(A=\left(3\dfrac{1}{3}+2,5\right):\left(3\dfrac{1}{6}-4\dfrac{1}{5}\right)-\dfrac{11}{31}\\ =\left(\dfrac{10}{3}+\dfrac{5}{2}\right):\left(\dfrac{19}{6}-\dfrac{21}{5}\right)-\dfrac{31}{11}\\ =\left(\dfrac{30}{6}+\dfrac{15}{6}\right):\left(\dfrac{95}{30}-\dfrac{126}{30}\right)-\dfrac{31}{11}\\ =\dfrac{45}{6}:\dfrac{-21}{30}-\dfrac{31}{11}\\ =\dfrac{15}{2}\times\dfrac{-10}{7}-\dfrac{31}{11}=-\dfrac{75}{7}-\dfrac{31}{11}=-\dfrac{825}{77}-\dfrac{217}{77}=\dfrac{-1042}{77}\)
\(B=\left(-6\right).10:\left[-0,25+\dfrac{1}{2}:\left(-2\right)\right]+1\dfrac{3}{4}\\ =-60:\left(\dfrac{-1}{4}+\dfrac{1}{2}.\dfrac{-1}{2}\right)+1\dfrac{3}{4}\\ =-60:\left(\dfrac{-1}{4}+\dfrac{-1}{4}\right)+1\dfrac{3}{4}\\ =-60:\left(\dfrac{-1}{2}\right)+1\dfrac{3}{4}=120+1\dfrac{3}{4}=121\dfrac{3}{4}\)
\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)
= \(\left(\frac{10}{3}+\frac{5}{2}\right):\left(\frac{19}{6}-\frac{21}{5}\right)-\frac{11}{31}\)
= \(\frac{35}{6}:\frac{-31}{30}-\frac{11}{31}\)
= \(\frac{175}{-31}\)- \(\frac{11}{31}\)
= -6
Nếu mình đúng thì các bạn k mình nhé
\(C=\left(\frac{3}{5}-\frac{4}{15}\right).\left(\frac{2}{7}-\frac{3}{14}\right)-\left(\frac{5}{9}-\frac{7}{27}\right).\left(1-\frac{3}{5}\right)+\left(1-\frac{11}{12}\right).\left(1+\frac{1}{12}\right)\)
\(C=\left(\frac{9}{15}-\frac{4}{15}\right).\left(\frac{4}{14}-\frac{3}{14}\right)-\left(\frac{15}{27}-\frac{7}{27}\right).\left(\frac{5}{5}-\frac{3}{5}\right)+\left(\frac{12}{12}-\frac{11}{12}\right).\left(\frac{12}{12}+\frac{1}{12}\right)\)
\(C=\frac{5}{15}.\frac{1}{14}.\frac{8}{27}.\frac{2}{5}.\frac{1}{12}.\frac{13}{12}\)
\(C=\frac{5.1.8.2.1.13}{15.14.27.5.12.12}\)
\(C=\frac{5.2.4.2.13}{3.5.14.27.5.4.3.2.2.3}\)
\(C=\frac{13}{3.14.27.5.3.3}\)
\(C=\frac{13}{51030}\)
=(10/3+5/2):(19/6-21/5)-11/31
=35/6:(-31/30)-11/31
=-175/31-11/31
=-6
CHÚC BN HOK TỐT NHA!! ^^