A = -3/13 – 7/17 + -5/19 + 10/13 + 24/17 – 14/19
b) B = 1,25 . 7/19 + 5/4 . 15/19 – 1.1/4 : 19/3
hợp lý nha , dễ mà .......................
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\dfrac{4}{5}\)+\(\dfrac{-5}{4}\)=\(\dfrac{0}{4}\)
\(\dfrac{-1}{3}\)+\(\dfrac{2}{5}-\dfrac{5}{6}\)=\(\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}\)=\(\dfrac{-23}{30}\)
\(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}\)=\(\dfrac{2}{3}-\dfrac{2}{5}\)=\(\dfrac{10}{15}-\dfrac{6}{15}\)=\(\dfrac{4}{15}\)
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
\(-\dfrac{3}{13}-\dfrac{7}{17}+\left(-\dfrac{5}{19}\right)+\left(-\dfrac{10}{13}\right)+\dfrac{24}{17}-\dfrac{4}{19}\)
\(=\left(-\dfrac{3}{13}-\dfrac{10}{13}\right)-\left(\dfrac{7}{17}-\dfrac{24}{17}\right)+\left(-\dfrac{5}{19}-\dfrac{4}{19}\right)\)
\(=-\dfrac{13}{13}-\left(-\dfrac{17}{17}\right)+-\dfrac{9}{19}\)
\(=-1+1+-\dfrac{9}{19}=-\dfrac{9}{19}\)
\(\dfrac{-3}{13}-\dfrac{7}{17}+\left(\dfrac{-5}{19}\right)+\left(\dfrac{-10}{13}\right)+\dfrac{24}{17}-\dfrac{4}{19}\)
=\(\left(\dfrac{-3}{13}+\dfrac{-10}{13}\right)+\left(\dfrac{-7}{17}+\dfrac{24}{17}\right)+\left(\dfrac{-5}{19}-\dfrac{4}{19}\right)\)
=-1+1+\(\dfrac{-9}{19}\)
=0+\(\dfrac{-9}{19}\) =\(\dfrac{-9}{19}\)
Bn thấy cái nào cùng mẫu hoặc dễ quy đồng thì nhóm vào 1 nhóm nha!
Xin đừng ném đá, mk chỉ nói đúng
Hội con 🐄 chúc bạn học tốt!!!
A = ( -4/5 + 4/3 ) + (-5/4 + 14/5) - 7/3
= 8/15 + 31/20 - 7/3
= 25/12 - 7/3
= -1/4
B = 8/3 x 2/5 x 3/8 x 10x 19/92
= 16/15 x 15/4 x 19/92
= 4x19/92
= 19/23
a) \(\dfrac{\dfrac{3}{14}-\dfrac{3}{17}+\dfrac{3}{19}}{\dfrac{5}{19}+\dfrac{5}{14}-\dfrac{5}{17}}=\dfrac{3\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}{5\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}=\dfrac{3}{5}\)
c) \(\dfrac{\dfrac{2}{7}+\dfrac{2}{5}+\dfrac{2}{17}-\dfrac{2}{193}}{\dfrac{3}{7}+\dfrac{3}{5}+\dfrac{3}{17}-\dfrac{3}{293}}=\dfrac{2\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}{3\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}=\dfrac{2}{3}\)
d)