tính: [1-1/4]* [1-1/9]*[1-1/16]*[1-1/25]*[1-1/36]
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\(\left(1-\frac{1}{4}\right).\left(1-\frac{1}{9}\right).\left(1-\frac{1}{16}\right).\left(1-\frac{1}{25}\right).\left(1-\frac{1}{36}\right)\)
\(=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.\frac{24}{25}.\frac{35}{36}=\frac{3.8.15.24.35}{4.9.16.25.36}=\frac{1.3.2.4.3.5.4.6.5.7}{2.2.3.3.4.4.5.5.6.6}\)
\(=\frac{\left(1.2.3.4.5\right).\left(3.4.5.6.7\right)}{\left(2.3.4.5.6\right).\left(2.3.4.5.6\right)}=\frac{1.7}{2.2}=\frac{7}{4}\)
Trả lời
(1-1/4).(1-1/9).(1-1/16).(1-1/25).(1-1/36)
=bước này thì bỏ ngoặc thôi, nên ko ghi lại nha
=1.(-1/4-1/9-1/16-1/25-1/36)
=1.(-900-400-225-144-100/3600)
=1.-1769/3600
=-1769/3600
Chắc sai òi !
\(\left(1-\frac{1}{4}\right).\left(1-\frac{1}{9}\right).\left(1-\frac{1}{16}\right).\left(1-\frac{1}{25}\right).\left(1-\frac{1}{36}\right)\)
\(=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.\frac{24}{25}.\frac{35}{36}\)
\(=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.\frac{4.6}{5.5}.\frac{5.7}{6.6}\)
\(=\frac{1.2.3.4.5}{2.3.4.5.6}.\frac{3.4.5.6.7}{2.3.4.5.6}\)
\(=\frac{1}{6}.\frac{7}{2}\)
\(=\frac{7}{12}\)
\(\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{9}\right)\times\left(1-\frac{1}{16}\right)\times\left(1-\frac{1}{25}\right)\times\left(1-\frac{1}{36}\right)\)
\(=\frac{3}{4}\times\frac{8}{9}\times\frac{15}{16}\times\frac{24}{25}\times\frac{36}{36}\)
\(=\frac{1.3}{2.2}\times\frac{2.4}{3.3}\times\frac{3.5}{4.4}\times\frac{4.6}{5.5}\times\frac{5.7}{6.6}\)
\(=\frac{1.2.3.4.5}{2.3.4.5.6}\times\frac{3.4.5.6.7}{2.3.4.5.6}\)
\(=\frac{1}{6}\times\frac{7}{2}\)
\(=\frac{7}{12}\)
(1-1/4)×(1-1/9)×(1-1/16)×(1-1/25)×(1-1/36)
=(4/4-1/4)×(9/9-1/9)×(16/16-1/16)×(25/25-1/25)×(36/36-1/36)
=3/4×8/9×15/16×24/25×35/36
=1×3×2×4×3×5×4×6×5×7/2×2×3×3×4×4×5×5×6×6
=(1×2×3×4×5)×(3×4×5×6×7)/(2×3×4×5×6)×(2×3×4×5×6)
=1/6×7/2
=7/12
1+4+9+16+25+....+100
Theo quy luật:
12+22+32+42+52+...+102
=385
Tacó cho công thức tổng quát: A2 - B2 = (A+B).(A-B)
A = (1-1/4)x(1-1/9)x(1-1/16)x(1-1/25)x(1-1/3...
= (1+1/2) x (1-1/2) x (1+1/3) x (1-1/3) x...x (1+1/n) x (1-1/n)
= (1+1/2) x (1+1/3) x (1+1/4) x ... x [1 + 1/(n-1) ] x (1 + 1/n)
x (1-1/2) x (1-1/3) x (1-1/4) x ... x [1 - 1/(n-1) ] x (1 - 1/n)
= 3/2 x 4/3 x 5/4 x ... x [ n/(n-1) ] x [ (n+1)/n ]
x 1/2 x 2/3 x 3/4 x ... x [ (n-2)/(n-1) ] x [ (n-1)/n]
Vậy dãy A là:
A = 1/2 x 2/3 x 3/2 x 3/4 x 4/3 x 4/5 x 5/4 x .... x [ (n-2)x(n-1) ] x [ (n-1)/n] x [ n/(n-1)] x [ (n+1)/n]
= 1/2 x 1 x 1 x 1 x ... x 1 x [(n+1)/n]