Tìm x biết:
\(\frac{25-x}{56}\)=\(\frac{6}{16}\)
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\(\frac{25-x}{56}=\frac{6}{16}\)
\(\frac{25-x}{56}=\frac{3}{8}\)
\(\frac{25-x}{56}=\frac{21}{56}\)
\(\Rightarrow25-x=21\)
\(\Rightarrow x=25-21\)
\(\Rightarrow x=4\)
Vậy x=4
=>(25-x)16=6x56=280
25-x=17.5
x=7.5=15/2
vậy x=15/2
Theo đề ta có: \(\frac{25-x}{56}=\frac{6}{16}\)
Ta rút gọn: \(\frac{25-x}{56}=\frac{3}{8}\)
\(\Leftrightarrow\)25 -x . 8 = 56 . 3
\(\Rightarrow\)25 - x . 8 = 168
\(\Rightarrow\)25 - x = 168 : 8
\(\Rightarrow\)25 - x = 21
\(\Rightarrow\) - x = 21 - 25
\(\Rightarrow\) - x = -4
\(\Rightarrow\) x = 4
Vậy x = 4.
25 - x / 56 = 6/16
( 25 - x ) : 56 = 6/16
25 - x = 6/16 x 56
25 - x = 21
x = 25 - 21
x = 4
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\frac{x}{56}=25-\frac{6}{16}\)
\(\frac{x}{56}=24\frac{5}{8}\)
\(\frac{x}{56}=24\frac{35}{56}\)
\(\frac{x}{56}=\frac{24\cdot56+35}{56}\)
\(\frac{x}{56}=\frac{1379}{56}\)
Vậy số cần tìm là \(1379\)
25-x/56 = 6/16
=> 2.(25-x)/112=7.6/112
=> 2.(25-x)= 42
=> 50 - 2x = 42
=> -2x = 50 - 42
=> -2x = 8
=> x = 8:(-2)
=> x = 4
\(\frac{x-2}{12}+\frac{x-2}{20}+\frac{x-2}{30}+\frac{x-2}{42}+\frac{x-2}{56}+\frac{x-2}{72}=\frac{16}{9}\)
\(\left(x-2\right)\cdot\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2\right)\cdot\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}\right)=\frac{16}{9}\)
\(\left(x-2\right)\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2\right)\cdot\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2\right)\cdot\left(\frac{3}{9}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2\right)\cdot\frac{2}{9}=\frac{16}{9}\)
\(x-2=\frac{16}{9}:\frac{2}{9}\)
\(x-2=\frac{16}{9}\cdot\frac{9}{2}\)
\(x-2=8\)
\(x=8+2\)
\(x=10\)
Vậy \(x=10\)
\(\left(x-2\right)\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)=\)\(=\frac{16}{9}\)
\(\left(x-2\right)\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2\right)\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2\right)\left(\frac{2}{9}\right)=\frac{16}{9}\)
2(x-2)=16
x-2=8
x=10
=> x-2.(1/12+1/20+1/30+1/42+1/56+1/72)=16/9
Đặt : Sáng = 1/12+1/20+1/30+1/42+1/56+1/72
=> Sáng = 1/3.4+1/4.5+1/5.6+1/6.7+1/7.8+1/8.9
=> Sáng = 1.(1/3-1/4+1/4-1/5+...+1/8-1/9
=> Sáng = 91.(1/3-1/9)
=> Sáng = 2/9
Thay Sáng vô biểu thức 1/12+1/20+1/30+1/42+1/56+1/72
Ta được :
x-2.2/9=16/9
giờ thì tự làm nha
=> x-2.(1/12+1/20+1/30+1/42+1/56+1/72)=16/9
Đặt : Sáng = 1/12+1/20+1/30+1/42+1/56+1/72
=> Sáng = 1/3.4+1/4.5+1/5.6+1/6.7+1/7.8+1/8.9
=> Sáng = 1.(1/3-1/4+1/4-1/5+...+1/8-1/9
=> Sáng = 91.(1/3-1/9)
=> Sáng = 2/9
Thay Sáng vô biểu thức 1/12+1/20+1/30+1/42+1/56+1/72
Ta được :
x-2.2/9=16/9
giờ thì tự làm nha
Ai k mk mk k lại
ta có:$\frac{x-1}{12}+\frac{x-1}{20}+\frac{x-1}{30}+\frac{x-1}{42}+\frac{x-1}{56}+\frac{x-1}{72}=\frac{16}{9}$
=> x+1(1/12+1/20+1/30+1/42+1/56+1/72)=16/9
=> x+1.2/9=16/9
=> x+1 = (16/9):(2/9)
=> x+1 = 8
=> x = 9
thông cảm mình ko đánh được dấu ngoặc tròn
[x-1].[1/12+1/20+1/30+1/42+1/56+1/72] =16/9
[x-1].[1/3.4+1/4.5+1/5.6+1/6.7+1/7.8+1/8.9]=16/9
[x-1].[1/3-1/9]=16/9
[x-1].2/9=16/9
x-1=16/9:2/9
x-1=8
x=7
Vậy x=7
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\Rightarrow\frac{25-x}{56}=\frac{3}{8}\)
\(\Rightarrow\left(25-x\right).8=56.3\)
\(\Rightarrow25.8-8x=168\)
\(\Rightarrow200-8x=168\)
\(\Rightarrow8x=200-168\)
\(\Rightarrow8x=32\)
\(\Rightarrow x=32:8\)
\(\Rightarrow x=4\)
Tham khảo nha !!!
Cách này dễ hơn nèk :
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{3}{8}\)
\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{21}{56}\)
\(\Leftrightarrow\)\(25-x=21\)
\(\Leftrightarrow\)\(x=25-21\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Chúc bạn học tốt ~