Những ai đang on trả lời cho mik câu này giải thik nha :
Tìm x trong các hỗn số : a. \(4\frac{3}{x}\)= \(\frac{47}{x}\)
b .\(x\frac{x}{15}\)= \(\frac{112}{5}\)
Gíup mik nha !!! Cái này có trong đề kiểm tra đó !!!
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a) \(\frac{x+1}{99}+\frac{x+2}{98}=\frac{x+3}{97}+\frac{x+4}{96}\)
\(\Rightarrow\frac{x+1}{99}+1+\frac{x+2}{98}+1=\frac{x+3}{97}+1+\frac{x+4}{96}+1\)
\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}-\frac{x+100}{97}-\frac{x+100}{96}=0\)
\(\Rightarrow\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}-\frac{1}{97}-\frac{1}{96}\right)=0\)
Vì 1/99 + 1/98 - 1/97 - 1/96 khác 0
=> x + 100 = 0 => x = -100
b) \(\frac{x-3}{47}+\frac{x-2}{48}=\frac{x-1}{49}+1\)
\(\Rightarrow\frac{x-3}{47}-1+\frac{x-2}{48}-1=\frac{x-1}{49}+1-2\)
\(\Rightarrow\frac{x-50}{47}+\frac{x-50}{48}-\frac{x-50}{49}=0\)
\(\Rightarrow\left(x-50\right)\left(\frac{1}{47}+\frac{1}{48}-\frac{1}{49}\right)=0\)
Vì 1/47 + 1/48 - 1/49 khác 0
Nên x -50 = 0 => x = 50
\(a,4\frac{3}{x}=\frac{47}{x}\)
\(\frac{4x+3}{x}=\frac{47}{x}\)
\(\Rightarrow4x^2+3x=47x\)
\(4x^2=47x-3x=44x\)
\(4x^2:4x=44x:4x\)
\(x=11\)
\(b,x\frac{x}{15}=\frac{112}{5}\)
\(\frac{15x+x}{15}=\frac{112}{5}\)
\(75x+5x=112.15\)
\(80x=1680\)
\(x=21\)
a, \(4\frac{3}{x}=\frac{47}{x}\)
\(\Leftrightarrow\frac{4x+3}{x}=\frac{47}{x}\)
\(\Leftrightarrow4x+3=47\)
\(4x=47-3\)
\(4x=44\)
\(x=44:4\)
\(x=11\)
b, \(x\frac{x}{15}=\frac{112}{5}\)
\(\Leftrightarrow\frac{15x+x}{15}=\frac{112}{5}\)
\(\Leftrightarrow\frac{16x}{15}=\frac{336}{15}\)
\(\Leftrightarrow16x=336\)
\(x=336:16\)
\(x=21\)
câu 2
\(...=\sqrt{\left(2-\sqrt{5}\right)^2}-\sqrt{\left(2+\sqrt{5}\right)^2}=\left|2-\sqrt{5}\right|-\left|2+\sqrt{5}\right|=-4\)
câu 1
\(P=\left(\frac{\sqrt{x}}{3+\sqrt{x}}+\frac{x+9}{\left(3-\sqrt{x}\right)\left(3+\sqrt{x}\right)}\right):\left(\frac{3\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}-3\right)}-\frac{1}{\sqrt{x}}\right)\)
\(=\left(\frac{\sqrt{x}\left(3-\sqrt{x}\right)+x+9}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}\right):\left(\frac{3\sqrt{x}+1-\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}-3\right)}\right)\)
\(=\frac{3\sqrt{x}+9}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}:\frac{2\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-3\right)}\)
\(=\frac{3}{\left(3-\sqrt{x}\right)}.\frac{\sqrt{x}\left(\sqrt{x}-3\right)}{2\sqrt{x}+4}=\frac{-3\sqrt{x}}{2\sqrt{x}+4}\)
\(P< -1\Leftrightarrow\frac{-3\sqrt{x}}{2\sqrt{x}+4}+1< 0\Leftrightarrow-\sqrt{x}+4< 0\Leftrightarrow\sqrt{x}>4\Leftrightarrow x>16\)
a) \(4\frac{3}{x}=\frac{47}{x}\)
=) \(\frac{4x+3}{x}=\frac{47}{x}\)
=) \(4x+3=47\)
=) \(4x=47-3=44\)
=) \(x=44:4=11\)
b) \(x\frac{x}{15}=\frac{112}{5}\)
=) \(\frac{15x+x}{15}=\frac{336}{15}\)
=) \(15x+x=336\)
=) \(16x=336\)
=) \(x=336:16=21\)
Ta có : \(4\frac{3}{x}=\frac{4x+3}{x}=\frac{47}{x}\)
=> 4x + 3 = 47
=> 4x = 44
=> x = 11
a) \(4\frac{3}{x}=\frac{47}{x}\)
\(\Rightarrow\frac{4\times x+3}{x}=\frac{47}{x}\)
\(\Rightarrow4\times x+3=47\)
\(4\times x=47-3\)
\(4\times x=44\)
\(x=44:4=11\)
b) \(x\frac{x}{15}=\frac{112}{5}\)
\(\Rightarrow\frac{x\times15+x}{15}=\frac{336}{15}\)
\(\Rightarrow\frac{x\times16}{15}=\frac{336}{15}\)
\(\Rightarrow x\times16=336\)
\(x=21\)
Chúc bn học tốt!!!!