Tính hợp lý
(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
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\(\Rightarrow P=\frac{3^{11}\left(5+4.3\right)}{3^9\left(5^2-2^3\right)}\)
\(\Rightarrow P=\frac{3^2.17}{17}=3^2=9\)
.(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^11.3):[3^9.(5^2-2^3)]
=(5.3^11+12.3^11):[3^9.17]
=3^11.(5+12):(3^9.17)
=(3^11.17):(3^9.17)
=17.(3^11:3^9)
=17.3^2
=17.9
=153
tk nha
bai cua kacura dung nhung 4 dong cuoi la sai to
co khong co kieu phan phoi nhu vay ma phai thay la 3^11:3^9( nhan 17 chia 17 thi khi nao cung nhan duoc ket qua giong nhau)
=3^2=9
1.(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^11.3):[3^9.(5^2-2^3)]
=(5.3^11+12.3^11):[3^9.17]
=3^11.(5+12):(3^9.17)
=(3^11.17):(3^9.17)
=17.(3^11:3^9)
=17.3^2
=17.9
=153
2.(12+22+32+...+992+1002).(36.333-108.111)
=2.(12+22+32+...+992+1002).(36.333-36.3.111)
=2.(12+22+32+...+992+1002).(36.333-36.333)
=2.(12+22+32+...+992+1002).0
=0
=\(\left[3^{11}.\left(5+4.3\right)\right]:\left[3^9.\left(5^2-2^3\right)\right]\)
=\(\left[3^{11}.17\right]:\left[3^9.17\right]=\left(3^{11}:3^9\right).17=9.17=153\)
\(\frac{5.3^{11}+4.3^{12}}{3^9.5^2-3^9.2^3}\)
\(=\frac{5.3^{11}+4.3.^{11}}{3^9.\left(5^2-2^3\right)}\)
\(=\frac{5.3^{11}+12.3^{11}}{3^9.\left(25-8\right)}\)
\(=\frac{3^{11}.\left(5+4\right)}{3^9.17}\)
\(=\frac{3^{11}.9}{3^9.17}\)
\(=\frac{3^9.3^2.9}{3^9.17}\)
\(=\frac{3^2.9}{17}\)
\(=\frac{9.9}{17}=\frac{81}{17}\)
Mình chuyển về phân số nhé. k mình nhé
P=(5.311+4.312):(39.52-39.23)
=[311.(5+4.3)]:[39.(52-23)]
=(311.17):(39.17)
=311.17:39:17
=32=9
Vậy P=9
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