giá trị của biểu thức 5-\(\frac{7}{5}\): \(\frac{3}{10}\)+ \(\frac{2}{5}\) là:
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\(\Rightarrow A=\frac{\frac{1}{2}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{8}-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{4}+\frac{1}{2}+\frac{3}{10}}\)
\(\Rightarrow A=\frac{\frac{1}{2}-\frac{1}{5}+\frac{1}{7}}{3.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{7}\right)}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{2}.\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right)}\)
\(\Rightarrow A=\frac{1}{3}+\frac{2}{3}\)
\(\Rightarrow A=1\)
\(\frac{6:\frac{3}{5}-1\frac{1}{6}\cdot\frac{6}{7}}{4\frac{1}{5}\cdot\frac{10}{11}+5\frac{2}{11}}=1\)
\(\frac{6:\frac{3}{5}-1\frac{1}{6}\times\frac{6}{7}}{4\frac{1}{5}\times\frac{10}{11}+5\frac{2}{11}}\)
\(=\frac{\frac{6}{1}:\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}}{\frac{21}{5}\times\frac{10}{11}\times\frac{57}{11}}\)
\(=\frac{\frac{6}{1}\times\frac{5}{3}-1}{\frac{210}{55}+\frac{57}{11}}\)
\(=\frac{\frac{30}{3}-1}{\frac{42}{11}+\frac{57}{11}}\)
\(=\frac{10-1}{\frac{99}{11}}\)
\(=\frac{9}{9}\)
\(=1\)
\(6:\frac{3}{5}-1\frac{1}{6}\)X \(\frac{6}{7}\) \(4\frac{1}{5}\)X \(\frac{10}{11}+5\frac{2}{11}\)
\(=\frac{33}{5}-\frac{7}{6}\)X \(\frac{6}{7}\) \(=\) \(\frac{21}{5}\)X \(\frac{10}{11}+\frac{57}{11}\)
\(=\frac{33}{5}-1\) \(=\frac{42}{11}+\frac{57}{11}\)
\(=\frac{28}{5}\) \(=\frac{99}{11}=9\)
Ta có :
\(5-\frac{7}{5}:\frac{3}{10}+\frac{2}{5}\)
\(=5-\frac{7}{5}x\frac{10}{3}+\frac{2}{5}\)
\(=5-\frac{14}{3}+\frac{2}{5}\)
\(=\frac{15}{3}-\frac{14}{3}+\frac{6}{15}\)
\(=\frac{1}{3}+\frac{6}{15}\)
\(=\frac{5}{15}+\frac{6}{15}\)
\(=\frac{11}{15}\)
Tham khảo nha !!!!
5 - \(\frac{7}{5}\): \(\frac{3}{10}\)+ \(\frac{2}{5}\)= 5 - \(\frac{14}{3}\)+ \(\frac{2}{5}\)
= \(\frac{1}{3}\)+ \(\frac{2}{5}\)
= \(\frac{11}{15}\)