Rút gọn P/S sau:
B=\(\frac{3+6+9+...+24}{30+33+...+60}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a. \(\frac{2x6x1}{33x24}=\frac{12}{792}=\frac{1}{66}\)
b. \(\frac{21x4}{9x7x5x3}=\frac{84}{945}=\frac{4}{45}\)
a. 2*6*1/33*24
bằng 12*1/33*24
bằng 1/33*2
bằng 1/66
b. 21*4/9*7*5*3
bằng 7*3*4/9*7*5*3
bằng 4/9*5
bằng 4/45.hk tốt
a) Ta có: \(\dfrac{25^{28}+25^{24}+25^{20}+...+25^4+1}{25^{30}+25^{28}+...+25^2+1}\)
\(=\dfrac{25^{24}\left(25^4+1\right)+25^{16}\left(25^4+1\right)+...+\left(25^4+1\right)}{25^{28}\left(25^2+1\right)+25^{24}\left(25^2+1\right)+...+\left(25^2+1\right)}\)
\(=\dfrac{\left(25^4+1\right)\left(25^{24}+25^{16}+25^8+1\right)}{\left(25^2+1\right)\left(25^{28}+25^{24}+...+1\right)}\)
\(=\dfrac{\left(25^4+1\right)\cdot\left[25^{16}\left(25^8+1\right)+\left(25^8+1\right)\right]}{\left(25^2+1\right)\left[25^{24}\left(25^4+1\right)+25^{16}\left(25^4+1\right)+25^8\left(25^4+1\right)+\left(25^4+1\right)\right]}\)
\(=\dfrac{\left(25^4+1\right)\left(25^8+1\right)\left(25^{16}+1\right)}{\left(25^2+1\right)\left(25^4+1\right)\left(25^{24}+25^{16}+25^8+1\right)}\)
\(=\dfrac{\left(25^8+1\right)\left(25^{16}+1\right)}{\left(25^2+1\right)\left[25^{16}\left(25^8+1\right)+\left(25^8+1\right)\right]}\)
\(=\dfrac{\left(25^8+1\right)\left(25^{16}+1\right)}{\left(25^2+1\right)\left(25^8+1\right)\left(25^{16}+1\right)}\)
\(=\dfrac{1}{25^2+1}=\dfrac{1}{626}\)
\(\frac{1}{2}\sqrt{48}-2\sqrt{75}-\frac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\frac{1}{3}}\)
=\(\frac{1}{2}\sqrt{3.4^2}-2\sqrt{3.5^2}-\sqrt{\frac{33}{11}}+5\sqrt{\frac{4}{3}}\)
\(=2\sqrt{3}-10\sqrt{3}-\sqrt{3}+10\sqrt{\frac{1}{3}}\)
\(=2\sqrt{3}-10\sqrt{3}-\sqrt{3}+\frac{10}{3}\sqrt{3}\)
\(=\left(2-10-1+\frac{10}{3}\right)\sqrt{3}\)
\(=\frac{-17}{3}\sqrt{3}\)
\(\sqrt{150}+\sqrt{1,6}.\sqrt{60}+4,5\sqrt{2\frac{2}{3}}-\sqrt{6}\)
\(=\sqrt{6.5^2}+\sqrt{96}+4,5\sqrt{\frac{8}{3}}-\sqrt{6}\)
\(=5\sqrt{6}+\sqrt{6.4^2}+4,5\frac{\sqrt{24}}{3}-\sqrt{6}\)
\(=5\sqrt{6}+4\sqrt{6}+\frac{4,5.2\sqrt{6}}{3}-\sqrt{6}\)
\(=8\sqrt{6}+3\sqrt{6}\)
\(=11\sqrt{6}\)
Tự hòi tự trl :D ?
\(\frac{1}{2}\sqrt{48}-2\sqrt{75}-\frac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\frac{1}{3}}\)
\(=\frac{1}{2}\sqrt{16.3}-2.5\sqrt{3}-\sqrt{3}-\frac{10}{3}\sqrt{3}\)
\(=2\sqrt{3}-10\sqrt{3}-\sqrt{3}-\frac{10}{3}\sqrt{3}\)
\(=-9\sqrt{3}+\frac{10}{3}\sqrt{3}=\left(-9+\frac{10}{3}\right)\sqrt{3}\)
\(=-\frac{17}{3}\sqrt{3}\)
\(\sqrt{150}+\sqrt{1,6}.\sqrt{60}+4,5.\sqrt{2\frac{2}{3}}-\sqrt{6}\)
\(=\sqrt{25.6}+\sqrt{1,6.60}+4,8\sqrt{\frac{8}{3}}-\sqrt{6}\)
\(=5\sqrt{6}+\sqrt{16.6}+4,5.\frac{1}{3}\sqrt{3^2.\frac{4.2}{3}}-\sqrt{6}\)
\(=9\sqrt{6}+3\sqrt{6}-\sqrt{6}=11\sqrt{6}\)
Rút gọn phân số 1371/3656 ta được phân số tối giản là:
B.3/8
Nhớ k cho mình nha!
1.
a) \(\frac{16}{24}-\frac{1}{3}=\frac{16}{24}-\frac{8}{24}=\)\(\frac{8}{24}=\frac{1}{3}\)
b) \(\frac{4}{5}-\frac{12}{60}=\frac{48}{60}-\frac{12}{60}=\frac{36}{60}=\frac{9}{15}\)
3.
a)\(\frac{17}{6}-\frac{2}{6}=\frac{17-2}{6}=\frac{15}{6}\)
b) \(\frac{16}{15}-\frac{11}{15}=\frac{16-11}{15}=\frac{5}{15}=\frac{1}{3}\)
c) \(\frac{19}{12}-\frac{13}{12}=\frac{19-13}{12}=\frac{6}{12}=\frac{1}{2}\)
\(\frac{10}{25}=\frac{10:5}{25:5}=\frac{2}{5}\)
\(\frac{5}{20}=\frac{5:5}{20:5}=\frac{1}{4}\)
\(\frac{6}{30}=\frac{6:6}{30:6}=\frac{1}{5}\)
\(\frac{60}{20}=\frac{60:20}{20:20}=3\)
\(\frac{4}{12}=\frac{4:4}{12:4}=\frac{1}{3}\)
\(\frac{24}{30}=\frac{24:6}{30:6}=\frac{4}{5}\)
\(\frac{25}{100}=\frac{25:25}{100:25}=\frac{1}{4}\)
\(\frac{60}{80}=\frac{60:20}{80:20}=\frac{3}{4}\)
\(\frac{9}{18}=\frac{9:9}{18:9}=\frac{1}{2}\)
\(\frac{60}{36}=\frac{60:12}{36:12}=\frac{5}{3}\)
\(\frac{72}{54}=\frac{72:18}{54:18}=\frac{4}{3}\)
\(\frac{35}{210}=\frac{35:35}{210:35}=\frac{1}{6}\)
4/12=1/3
24/30=4/5
25/100=1/4
60/80=3/4
9/18=1/2
60/36=5/3
72/54=4/3
35/210=1/6
Tách ra 2 phần
Tử trước: Số các số hạng là:
( 24 - 3 ) : 3 + 1 = 8 (số)
Tổng là:
( 24 + 3 ) x 8 : 2 = 108
Mẫu: Số các số hạng là:
( 60 - 30 ) : 3 + 1 = 11 (số)
Tổng là:
( 60 + 30 ) x 11 : 2 = 495
Vậy ta có phân số: \(\frac{108}{495}=\frac{12}{55}\)