43 . 59 + 57 . 59 - 43 . 21 - 57 . 21 = ???
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a,24.57+43.24
=24.(57+43)
=24.100
=2400
b,12.19+12
=12.(19+1)
=12.20
=12.10.2
=120.2
=240
c,43.27+93.43+57.61+59.57
=43.(27+93)+57.(61+59)
=43.120+57.120
=120.(43+57)
=120.100
=12000
d,64.6+81.4+17.6
=64.6+27.3.2.2+17.6
=64.6+54.6+17.6
=(64+54+17).6
=135.6
=810
a) 24 . 57 + 43 . 24
= 24 . (57 + 43)
= 24 . 100
= 2400
b) 12 . 19 + 12
= 12 . (19 + 1)
= 12 . 20
=240
c) 43 . 27 + 93 . 43 + 57 . 61 +59 . 57
= 43 . ( 27 + 93) + 57 . (61 + 59)
= 43 . 120 + 57 . 120
= 120 . (43 + 57)
= 120 . 100
= 12000
43 x 27 + 93 x 43 + 57 x 61 + 59 x 57
= 43 x ( 27 + 93 ) + 57 x ( 61 + 59 )
= 43 x 120 + 57 x 120
= 120 x ( 43 + 57 )
= 120 x 100
= 1200
b) 64 x 6 + 81 x 4 + 17 x 6
= 6 x ( 64 + 17 ) + 81 x 4
= 6 x 81 + 81 x 4
= 81 x ( 6 + 4 )
= 81 x 10
= 810
A) =43 x (27+93)+57*(61+59)
=43*120+57*120
=120*(43+57)
=120*100
=12000
Mình bạn chép đề sai, đề bài như này mới đúng nhé, bạn check lại xem đề nha :
\(\frac{59-x}{41}+\frac{57-x}{43}+\frac{55-x}{45}=-3\)
\(\Leftrightarrow\frac{59-x}{41}+1+\frac{57-x}{43}+1+\frac{55-x}{45}+1=0\)
\(\Leftrightarrow\frac{100-x}{41}+\frac{100-x}{43}+\frac{100-x}{45}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\frac{1}{43}+\frac{1}{45}+\frac{1}{41}\right)=0\)
\(\Leftrightarrow100-x=0\left(\frac{1}{41}+\frac{1}{43}+\frac{1}{45}\ne0\right)\)
\(\Leftrightarrow x=100\)
Vậy : \(x=100\)
a, 119 + 24 + 81
= ( 119 + 81 ) + 24
= 200 + 24
= 224
b, 16 . 6 . 125
= 16 . 125 . 6
= 2000 . 6
= 12000
c, 25 . 104
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d, 12 . 19 + 12
= 12 . 19 + 12 . 1
= 12 . ( 19 + 1 )
= 12 x 20
= 240
e, 43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93 ) + ( 61 + 59 ) . 57
= 43 . 120 + 120 . 57
= 120 . 43 + 120 . 57
= 120 . ( 43 + 57 )
= 120 . 100
= 12000
a/ 199 + 24 + 81
= (119+81) + 24
= 200 + 24
= 224
b/ 16 . 6 . 125
= ( 16 . 125) . 6
= 2000 . 6
= 12000
c/ 25 . 104
= 25 . ( 100 + 4 )
= 25 . 100 + 25 . 4
= 2500 + 100
= 2600
d/43 . 27 + 93 . 43 + 57 . 61 + 59 . 57
= 43 . ( 27 + 93) + 57 . ( 61+ 59)
= 43 . 130 + 57 . 130
= (43 + 57) . 130
= 100 . 130
= 1300
2 . 53 . 27 + 6 . 9 . 87 - 3 . 18 . 40
= 2. 53 . 9 . 3 + 2. 3 .9 .87 - 3 .2 .9 .40
= 54.53+54.87-54.40
=54(53+87-40)
=54. 100=5400
12 . 25 + 29 . 25 + 59 . 25
= 25 . ( 12+29+59)
=25 . 90
=2250
43 . 37 + 93 . 43 + 57 . 61 + 69 . 57
= 43.(37+93)+57(61+69)
=43.130+57.130
=130.(43+57)
=130.100
=13 000
12 . 53 + 53 . 172 - 53
=53(12+172-1)
=53.184
=9752
35 . 54 + 35 . 58 + 65 . 75 + 65 . 45
=35(54+58)+65(75+45)
=35.112+65.120
=3920+7800
=11720
39 . 8 + 70 . 3 + 31 . 8
=8(39+31)+70.3
=8.70+70.3
=70.(8+3)
=70.11
=770
\(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\Leftrightarrow\dfrac{59-x}{41}+1+\dfrac{57-x}{43}+1+\dfrac{55-x}{45}+1+\dfrac{53-x}{47}+1+\dfrac{51-x}{49}+1=0\)
=>100-x=0
hay x=100
ta có: (59-x)/41 +(57-x)/43 +(55-x)/45 +(53-x)/47 +(51-x)/49 =-5
<=>[(59-x)/41 +1 ] +[(57-x)/43 +1] +[(55-x)/45 +1] +[(53-x)/47 +1] +[(51-x)/49 +1] =0
<=>(59-x-41)/41 + (57-x-43)/43 +(55-x-45)/45 +(53-x-47)/47 +(51-x-49)/49 =0
<=>(100-x)/41 + (100-x)/43 + (100-x)/45 +(100-x)/47 + (100-x)/49 =0
<=>(100-x).( 1/41 + 1/43 + 1/45 + 1/47 + 1/49 ) =0
mà (1/41 + 1/43 + 1/45 + 1/47 + 1/49) khác 0 nên 100-x =0 <=>x=100
vậy nghiệm của pt là x=100
\(43\cdot59+57\cdot59-43\cdot21-57\cdot21\)
\(=59\left(43+57\right)-21\left(43+57\right)\)
\(=3800\)
=59.(43+57)-21.(43+57)
=59.100-21.100
=100.(59-21)
=100.38
=3800