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Câu đầu:
12/5 - X x 3/4 =5/4
X x 3/4 =12/5 - 5/4 ra X x 3/4 = 23/20 , X = 23/20 : 3/4 ,X=23/15
Câu hai:
X : 3/5 + 3/8 =15/8
X : 3/5 =15/8 - 3/8 ra X : 3/5 = 15/8 , X= 15/8 x 3/5,X= 9/8
a) x + 1/15 = 1/3 - 1/4 = 4/12 - 3/12 = 1/12.
=> x = 1/12 - 1/15 = 5/60 - 4/60 = 1/60.
b) x - 5/12 = 1/3 + 1/4 = 4/12 + 3/12 = 7/12.
=> x = 7/12 + 5/12 = 1
c) x x 2/7 = 3/4 x 4/15 = 1/5
=> x = 1/5 : 2/7 = 1/5 x 7/2 = 7/10
d) x : 3/8 = 4/3 : 3/6 = 4/3 x 2 = 8/3
=> x = 8/3 x 3/8 = 1
hộ mik nha
a)\(2.x-\frac{3}{2}=\frac{1}{2}\)
\(2x=\frac{4}{2}\)
\(x=\frac{4}{2}:2\)
\(x=1\)
Vậy x=1
b)\(\frac{8}{13}.x+\frac{5}{13}.x=\frac{1}{10}\)
\(x.\left(\frac{8}{13}+\frac{5}{13}\right)=\frac{1}{10}\)\
\(x.1=\frac{1}{10}\)
\(x=\frac{1}{10}\)
Vậy x=\(\frac{1}{10}\)
c)\(\frac{2}{15}+\frac{7}{15}.x=\frac{1}{15}\)
\(\frac{7}{15}x=\frac{-1}{15}\)
x=\(\frac{-1}{7}\)
Vậy \(x=\frac{-1}{7}\)
\(\frac{3}{2}\cdot x-\frac{3}{2}=\frac{1}{2}\) \(\frac{8}{13}\cdot x+\frac{5}{13}\cdot x=\frac{1}{10}\)
\(\frac{3}{2}\cdot x=\frac{3}{2}+\frac{1}{2}=2\) \(\left[\frac{8}{13}+\frac{5}{13}\right]\cdot x=\frac{1}{10}\)
\(x=2:\frac{3}{2}\) \(1\cdot x=\frac{1}{10}\)
x=\(\frac{4}{3}\) \(x=\frac{1}{10}:1\)
Vậy x=\(\frac{4}{3}\) \(x=\frac{1}{10}\)
Vậy x=\(\frac{1}{10}\)
c,\(\frac{2}{5}+\frac{7}{15}\cdot x=\frac{1}{15}\)
\(\frac{7}{15}\cdot x=\frac{1}{15}-\frac{2}{5}=\frac{-1}{3}\)
\(x=\frac{-1}{3}:\frac{7}{15}\)
\(x=\frac{-5}{7}\)
Vậy x=\(\frac{-5}{7}\)
a,\(\frac{3}{8}\)x X + 1 = \(\frac{15}{8}\)
\(\frac{3}{8}\)x X = \(\frac{15}{8}\)- 1
\(\frac{3}{8}\)x X = \(\frac{7}{8}\)
X = \(\frac{7}{8}\): \(\frac{3}{8}\)
X = \(\frac{7}{3}\)
b, \(\frac{1}{5}\)+ \(\frac{4}{5}\)x X = \(\frac{7}{3}\)
1 x X = \(\frac{7}{3}\)
X = \(\frac{7}{3}\): 1
X = \(\frac{7}{3}\)
=>9<6(8x-15)<18
=>6(8x-15)=12
=>8x-15=2
=>8x=17
=>x=17/8
(X+15) : 3 = 24
X+15 = 24 x 3
X+15 = 72
X= 72-15
X=57
(x+15):3=3x8
(x+15):3=24
(x+15)=24x3
x+15=72
x=72-15
x=57
vậy x=57