Question

[Nguyễn Bình Phương Nghi]

Vậy có ai biết làm ko giúp tớ nhé !

4) So sánh A=2005^2005+1/2005^2006+1 và B=2005^2004+1/ 2003^2009+2 

Giúp mình nha! 

Answer 1

[Nguyễn Nhân Dương]

$A=\frac{{2005}^{2005}+1}{{2005}^{2006}+1}<\frac{{2005}^{2005}+1+2004}{{2005}^{2006}+1+2004}=\frac{2005.({2005}^{2004}+1)}{2005.({2005}^{2005}+1)}==\frac{{2005}^{2004}+1}{{2005}^{2005}+1}=B.$

Vậy A < B

Answer 2

[Nguyễn Nhân Dương]

$A=\frac{{2005}^{2005}+1}{{2005}^{2006}+1}<\frac{{2005}^{2005}+1+2004}{{2005}^{2006}+1+2004}=\frac{2005.({2005}^{2004}+1)}{2005.({2005}^{2005}+1)}==\frac{{2005}^{2004}+1}{{2005}^{2005}+1}=B.$

Vậy A < B