Question

[Yêu bóng đá]

tính nhanh:

a, (2+4+6+.....+100) . (36.333-108.111)

b, 19991999.1998 - 19981998.1999

Answer 1

[Minh Anh]

a) (2+4+6+.....+100) . (36.333-108.111)

= (2+4+6+...+100).(36.111.3-108.111)

= (2+4+6+...+100).(108.111-108.111)

= (2+4+6+...+100).0

=0

b) 19991999.1998-19981998.1999

= 1999.10001.1998-1998.10001.1999

= 0

Answer 2

[Thanh Tùng DZ]

a) ( 2 + 4 + 6 + ... + 100 ) . ( 36.333 - 108.111 )

=  ( 2 + 4 + 6 + ... + 100 ) . ( 36.3.111 - 108.111)

= ( 2 + 4 + 6 + ... + 100 ) . ( 108.111 - 108.111 )

= ( 2 + 4 + 6 +... + 100 ) . 0

= 0

b) 19991999.1998 - 19981998 . 1999

= 1999.10001.1998 - 1998.10001 . 1999

= 0