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ta có : \(\frac{4^{17}+64}{4^{16}+16}=\frac{2^{34}+2^6}{2^{32}+2^4}=\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}=2^2=4\)
Ta có: \(\frac{4^{17}+64}{4^{16}+16}\) = \(\frac{2^{34}+2^6}{2^{32}+2^4}\) = \(\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}\) = \(\frac{2^6}{2^4}\) = \(\frac{64}{16}\) = 4
1.
\(B=20182018.2017-20172017.2018\)
\(B=2018.10001.2017-2017.10001.2018\)
\(B=0\)
1 B=20182018.2017-20172017.2018
B=2018.10001.2017-2017.10001.2018
B=0
2 C=12+22+32+...+1002
C=1(1+0)+2(1+1)+3(1+2)+...+100(1+99)
C=1+2+1.2+3+2.3+...+100+99.100
C=(1+2+3+...+100)+(1.2+2.3+...+99.100)
C=[(1+100).100:2]+[(99.100.101):3]
C=5050+333300
C=338350
25.78 + 52 . 12 - 25 . 10
= 25 . 78 + 25 . 12 - 25 . 10
= 25 . ( 78 + 12 - 10 )
= 25 . 80
= 2000
\(25.78+5^2.12-25.10\)
\(=1950+300-250\)
\(=2000\)
\(k\)đi nha bạn
\(-1999.19981998+19991999.1998\)
\(=-1999.\left(19980000+1998\right)+1998.\left(19990000+1999\right)\)
\(=-1999.19980000-1999.1998+1998.19990000+1998.1999\)
\(=\left(1998.1999-1999.1998\right)+\left(1998.19990000-1999.19980000\right)\)
\(=\left(1998.1999-1999.1998\right)+10000\left(1998.1999-1999.1998\right)=0\)
1.(-1999).19981998+19991999.1998
=(-1998-1).19981998+19991999.1998
=(-1998).19981998-19981998+19991999.1998
=(-19981998+19991999).1998-19981998
=10001.1998-19981998
=0
a) (417+64):(416+16)
= (417+43):(416+42)
=420:418
=42=16
b)83:24+513:511.30
=(23)3:24+52.1
=26:24+25
=22+25
=4+25=29
c)33.48+34.42+81.42
=33.48+33.3.42+33.3.42
=33.48+33.126+33.126
=33.(48+126+126)
=27.300
=8100