NL
1
K
Khách
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NL
1
TT
27 tháng 9 2017
=(22)6.(32)5+(2.3)9.23.3.5/(23)4.312-(2.3)11
=212.310+29.39.23.3.5/212.312-211.311
=212.310+212.310.5/211.311(2.3-1)
=212.310(1+5)/211.311.5
=2.6/3.5
=4/5
27 tháng 11 2016
\(\frac{10.4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2.5.\left(2.2\right)^6.\left(3.3\right)^5+\left(2.3\right)^9.3.40}{\left(2.2.2\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2.5.2^6.2^6.3^5.3^5+2^9.3^9.3.40}{2^4.2^4.2^4.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{13}.5.3^{10}+2^{12}.5.3^{10}}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.5.3^{10}.\left(2+1\right)}{2^{11}.3^{11}\left(2.3-1\right)}=\frac{2^{12}.5.3^{11}}{2^{11}.5.3^{11}}=2\)
KD
3
BD
1
6 tháng 8 2017
\(\dfrac{10.4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\dfrac{5.2.2^{12}.3^{10}+3^9.2^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{5.2^{13}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3-1\right)}=\dfrac{2^{12}.3^{10}.5\left(2+1\right)}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^{11}.2.3^{10}.5.3}{2^{11}.3^{10}.3.5}=2\)
LK
1
24 tháng 9 2016
\(\frac{10.\left(4^6.9^5-6^9.120\right)}{8^4.3^{12}-6^{11}}=\frac{10.4^6.9^5-10.6^9.120}{\left(2^3\right)^4.3^{12}-6^{11}}=\frac{2.5.\left(2^2\right)^6.\left(3^2\right)^5-2.5.6^9.2^3.3.5}{2^{12}.3^{12}-6^{11}}\)
\(=\frac{2.5.2^{12}.3^{10}-2^4.3.5^2.6^9}{6^{12}-6^{11}}=\frac{2^{13}.5.3^{10}-6.2^3.5^2.6^9}{6^{11}.\left(6-1\right)}\)
\(=\frac{6^{10}.2^3.5-6^{10}.2^3.5^2}{6^{11}.5}=\frac{6^{10}.2^3.5.\left(1-5\right)}{6^{11}.5}\)
\(=\frac{2^3.\left(-4\right)}{6}=\frac{8.\left(-4\right)}{6}=\frac{-32}{6}=\frac{-16}{3}\)
27 tháng 5 2016
46.95+69.120 / 84.312-611
=(22)6.(32)5+(2.3)9.23.3.5 / (23)4.312-(2.3)11
=212.310+29.39.23.3.5 / 212.312-211.311
=212.310+212.310.5 / 211.311.(2.3-1)
=212.310.(1+5) / 211.311.(6-1)
=212.310.6 / 211.311.5
=213.311 / 211.311.5
=22/5
=4/5
\(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\dfrac{\left(2^2\right)^6.\left(3^2\right)^5_{\cdot}+\left(2.3\right)^9.2^3.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3-1\right)}\)
\(=\dfrac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(6-1\right)}\)
\(=\dfrac{2^{12}.3^{10}.6}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^{13}.3^{11}}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^2}{5}\)
\(=\dfrac{4}{5}\)