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\(=\frac{1.2.4\left(1+2.2.2+4.4.4+8.8.8+16.16.16\right)}{1.3.4\left(1+2.2.2+4.4.4+8.8.8+16.16.16\right)}=\frac{2}{3}\)
\(\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}=\frac{2.4+2.4.2.2.2.2+4.2.4.4.4+4.2.2.4.2.4.8}{3.4+2.3.2.4.2+4.3.4.4.4+4.2.4.3.2.4.8}\)
\(=\frac{2.4\left(1+2.2.2+4.4.4+2.4.2.4.8\right)}{3.4\left(1+2.2.2+4.4.4+2.4.2.4.8\right)}\)
\(=\frac{2.4}{3.4}\)
\(=\frac{2}{3}\)
\(\dfrac{\text{2.4 + 2.4.8 + 4.8.16 + 8.16.32 + 16.32.64 }}{3.4+2.6.8+4.12.16+8.24.32+16.48.64}\)
= \(\dfrac{2+4+8+16+32}{3+6+12+24+48}\)= \(\dfrac{2+2+2+2+2}{3+3+3+3+3}\)
= \(\dfrac{10}{15}\) = \(\dfrac{2}{3}\)
\(\frac{3.7.8.13}{14\cdot15\cdot26}=\frac{3\cdot7\cdot8\cdot13}{2\cdot7\cdot3\cdot5\cdot2\cdot13}=\frac{8}{5\cdot2\cdot2}=\frac{8}{20}=\frac{2}{5}\)
\(\frac{3.7.8.13}{14.15.26}=\frac{3.7.2^3.13}{2.7.3.5.13.2}=\frac{1.7.2.1}{1.1.1.5.1.1}=\frac{14}{5}\)
\(\frac{11.8-11.3}{17-6}=\frac{11.\left(8-3\right)}{11}=\frac{11.5}{11}=\frac{1.5}{1}=\frac{5}{1}=5\)
\(\frac{-17.13+17.2}{11.2-11.9}=\frac{-17.13+\left(-17\right).2}{11.\left(2-9\right)}=\frac{-17.\left(-13+2\right)}{11.\left(-7\right)}=\frac{-17.\left(-11\right)}{11.\left(-7\right)}=\frac{-17.\left(-1\right)}{-1.\left(-7\right)}=\frac{17}{7}\)
\(\frac{7}{9.10^2-2.10^2}=\frac{7}{100\left(9-2\right)}=\frac{7}{100.7}=\frac{7}{700}=\frac{1}{100}\)
mình làm được tới đó thôi, hihi.