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\(a,\dfrac{-3}{7}-x=\dfrac{8}{9}\\ =>x=-\dfrac{3}{7}-\dfrac{8}{9}\\ =>x=-\dfrac{83}{63}\)
\(b,\left(\dfrac{3}{10}-x\right):\dfrac{2}{5}=\dfrac{3}{5}\\ =>\dfrac{3}{10}-x=\dfrac{3}{5}\text{×}\dfrac{2}{5}=\dfrac{6}{25}\\ =>x=\dfrac{3}{10}-\dfrac{6}{25}=\dfrac{3}{50}\)
a: =>x=-3/7-8/9=-83/63
b: \(\Leftrightarrow\left(\dfrac{3}{10}-x\right)=\dfrac{3}{5}:\dfrac{2}{5}=\dfrac{3}{2}\)
=>x=3/10-3/2=-6/5
c: \(\Leftrightarrow\left(x-\dfrac{1}{2}\right)^2=4\)
=>x-1/2=2 hoặc x-1/2=-2
=>x=5/2 hoặc x=-3/2
d: =>1/8x+1/2=5/2-3/4=10/4-3/4=7/4
=>1/8x=7/4-1/2=5/4
=>x=10
\(\dfrac{5}{12}-\dfrac{3}{4}-\dfrac{5}{-3}\\ =\dfrac{5}{12}-\dfrac{3}{4}+\dfrac{5}{3}\\ =\dfrac{5}{12}-\dfrac{9}{12}+\dfrac{20}{12}\\ =\dfrac{5-9+20}{12}\\ =\dfrac{16}{12}\\ =\dfrac{4}{3}\)
5/12-3/4-5/-3
=5/12-9/12-(-20/12)
=5/12-9/12+20/12
=16/12=4/3