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\(a,=15\left(\dfrac{2121}{4343}+\dfrac{222222}{434343}\right)=15\left(\dfrac{21}{43}+\dfrac{22}{43}\right)=15\cdot1=15\)
A = 2006 x 125 + 1000 / 126 x 2005 - 888
A = (2005 + 1) x 125 + 1000 / (125 + 1) x 2005 - 888
A = 2005 x 125 + 125 + 1000 / 125 x 2005 + 2005 - 888
A = 2005 x 125 + 1125 / 125 x 2005 + 1117
A = 1125 / 1117
\(\frac{2006\cdot125+1000}{126\cdot2005-888}=\frac{2005\cdot125+125+1000}{125\cdot2005+2005-888}=\frac{2005\cdot125+1125}{125\cdot2005+1117}\)
=> không tính nhanh được
2006.125 + 1000 / 126. 2005 - 880 = ( 2005 + 1 ). 125 + 1000 / (125+1). 2005 - 880 =2005. 125 + 125 + 1000 / 2005. 125 + 2005 -880 =2005. 125 = 1125 / 2005 + 125 + 1125
\(B=\frac{2006\cdot125+1000}{126\cdot2005-880}\)
= \(\frac{2005\cdot125+125+1000}{2005\cdot126-880}=\frac{2005\cdot125+1125}{2005\cdot126-880}\)
=\(\frac{2005\cdot125+1125}{2005\cdot125+125-880}=1,007523912\)
\(=\frac{2006.2004+2006-1}{2004.2006+2005}=\frac{2006.2004+2005}{2004.2006+2005}=1\)
=2006×(2004+1)-1/2004×2006+2005
=2006×2004+2006×1-1/2004×2006+2005
=2006×2004+2005/2004×2006+2005
=1
\(\frac{\left(2005+1\right).125+1000}{\left(125+1\right).2005-888}\)
= \(\frac{2005.125+125+1000}{125.2005+2005-888}\)
= \(\frac{2005.125+1125}{125.2005+1117}\)
= \(\frac{250625+1125}{250625+1117}\)
= \(\frac{125875}{125871}\)