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\(\frac{1}{3}:x-\frac{2}{3}=\frac{5}{6}+\frac{7}{8}\)
\(\frac{1}{3}:x-\frac{2}{3}=\frac{41}{24}\)
\(\frac{1}{3}:x=\frac{19}{8}\)
\(x=\frac{8}{57}\)
\(\frac{2}{5}-x:\frac{3}{5}=\frac{6}{7}\)
\(x:\frac{3}{5}=\frac{-16}{35}\)
\(x=\frac{-48}{175}\)
\(\frac{4}{5}-\frac{26}{m}=\frac{-8}{15}\)
\(\frac{26}{m}=\frac{4}{3}\)
=> 26 x 3 = m x 4
78 = m x 4
m = 19,5
Câu 1 :\(\frac{1}{3}\div x-\frac{2}{3}=\frac{5}{6}+\frac{7}{8}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{5}{6}+\frac{7}{8}+\frac{2}{3}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{4\cdot5}{24}+\frac{7\cdot3}{24}+\frac{2\cdot8}{24}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{20}{24}+\frac{21}{24}+\frac{16}{24}\)
\(\Leftrightarrow\frac{1}{3x}=\frac{57}{24}\)
\(\Leftrightarrow24=57\cdot3x\)
\(\Leftrightarrow24=171x\)
\(\Leftrightarrow x=\frac{24}{171}=\frac{8}{57}\)
Câu 2: \(\frac{2}{5}-x\div\frac{3}{5}=\frac{6}{7}\)
\(\Leftrightarrow\frac{-5x}{3}=\frac{6}{7}-\frac{2}{5}\)
\(\Leftrightarrow\frac{-5x}{3}=\frac{5\cdot6}{35}-\frac{2\cdot7}{35}\)
\(\Leftrightarrow\frac{-5x}{3}=\frac{30}{35}-\frac{14}{35}\)
\(\Leftrightarrow-\frac{5x}{3}=\frac{16}{35}\)
\(\Leftrightarrow-175x=48\)
\(\Leftrightarrow x=-\frac{48}{175}\)
Câu 3: \(\frac{4}{5}-\frac{26}{m}=-\frac{8}{15}\)
\(\Leftrightarrow\frac{26}{m}=\frac{4}{5}-\left(-\frac{8}{15}\right)\)
\(\Leftrightarrow\frac{26}{m}=\frac{4}{5}+\frac{8}{15}\)
\(\Leftrightarrow\frac{26}{m}=\frac{12}{15}+\frac{8}{15}\)
\(\Leftrightarrow\frac{26}{m}=\frac{20}{15}\)
\(\Leftrightarrow20m=26\cdot15=390\)
\(\Leftrightarrow m=\frac{390}{20}=\frac{39}{2}\)
\(-12\left(x-5\right)+7\left(x-3\right)=5\)
\(-12x-\left(-60\right)+7x-21=5\)
\(-12x+60+7x-21=5\)
\(\left(-12x+7x\right)+60-21=5\)
\(-5x+39=5\)
\(-5x=5-39=-34\)
\(x=\frac{-34}{-5}=\frac{34}{5}\)
1.4x - 5(-3+x)=7
4x - 5(x-3) =7
4x - 5x + 15=7
-1x + 15=7
-1x =-8
=> x =8
2.5(x-3) - 2(x+6)=9
5x - 15 -2x -12=9
5x - 2x -15 - 12=9
5x - 2x=9 + 12 + 15
5x - 2x= 36
3x = 36
=> x = 12
3.4(x-1) - 3(x-2)=15
4x - 4 - 3x + 6=15
4x - 3x =15 - 6 + 4
4x - 3x = 13
=> x = 13
Nhớ mink nhoa pn
\(-2,5\times\left(x+\dfrac{1}{5}\right)=\dfrac{7}{5}\)
\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}:\left(-2,5\right)\)
\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}\times\left(-\dfrac{2}{5}\right)\)
\(\Leftrightarrow x+\dfrac{1}{5}=-\dfrac{14}{25}\)
\(\Leftrightarrow x=-\dfrac{19}{25}\)
Câu 1:
a) 2(x-3)-3(x-5)=4(3-x)-18
<=> 3x-6-3x+15-12+4x+18=0
<=> 4x+15=0
<=> 4x=-15
<=> x=-15/4
b) -2(2x-8)+3(4-2x)=-57-5(3x-7)
<=> -4x+16+12-6x+57+15x-35=0
<=> -5x+50=0
<=> -5x=-50
<=> x=10
c) 3|2x2-7|=33
<=> |2x2-7|=11
<=> \(\orbr{\begin{cases}2x^2-7=11\\2x^2-7=-11\end{cases}\Leftrightarrow\orbr{\begin{cases}2x^2=18\\2x^2=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x^2=9\\x^2=-2\end{cases}\Leftrightarrow}x=\pm3}\)
d) có 9x+17=3(3x+2)+11
=> 11 chia hết cho 3x+2
=> 3x+2 thuộc Ư (11)={-11;-1;1;11}
ta có bảng
3x+2 | -11 | -1 | 1 | 11 |
x | -13/3 | -1 | -1/3 | 3 |
Câu 2:
xy-5x+y=17
<=> x(y-5)+(y-5)=12
<=> (y-5)(x+5)=12
=> y-5; x+5 \(\inƯ\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\)
lập bảng tương tự câu 1
7( 5-x)+5(x-2)=15
=> 35-7x+5x-10 =15
=>25 - 2x = 15
=> 2x =10
=> x = 5
\(7\left(5-x\right)+5\left(x-2\right)=15\)
\(\Leftrightarrow35-7x+5x-10=15\)
\(\Leftrightarrow-2x=-10\)
\(\Leftrightarrow x=5\)