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như này hả:
\(36\cdot28+36\cdot82+64\cdot96+64\cdot41\)
\(=36\cdot\left(28+82\right)+64\cdot\left(96+41\right)\)
\(=36\cdot110+64\cdot137\)
\(=3960+8768=12728\)
tiick mk nha.
#ngố
a). 25.5.4.27.2=(25.4).(5.2).27=100.10.27=1000.27=27000
b). 28.64+28.36=28.(64+36)=28.100=2800
a/ 26176
b/ 8
c/472392
d/ Ko tính dc
Thấy mình đẳng cấp ko
Cho mình 10 k nhé
a 86+14+357=100+357=457
b 72+128+69=200+69=269
c (25.4).(5.2).4.27
=100.10.4.27
=1000.4.27
=4000.27=64000
d 28. (64+36)=28.100=2800
nha
a) 86 + 357 + 14 b ) 72 + 69 +128
= ( 86 + 14 ) + 357 = ( 72 + 128 ) + 69
= 100 + 357 = 200 + 69 = 269
= 457
c) 25 . 5 . 4 . 27 .2
= ( 25.4).(5.2).27
= 100 x 10 x 27
= 1000 x 27
= 27 000
d) 28.64+28.36
= 28 . ( 64 + 36 )
= 28.100
= 2800
\(\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{n.\left(n+3\right)}\)=\(\frac{1}{3}\)(\(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{n}+\frac{1}{n+3}\))=\(\frac{1}{5}-\frac{1}{n+3}=\frac{101}{1540}:\frac{1}{3}=\frac{303}{1540}\)
=>\(\frac{1}{n+3}=\frac{1}{5}-\frac{303}{1540}=\frac{1}{308}\)vậy n= 308+3=311
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right).x=\frac{23}{45}\)
\(\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right).x=\frac{23}{45}\)
\(\left(\frac{1}{1.2}-\frac{1}{9.10}\right).x=\frac{23}{45}\)
\(\frac{22}{45}.x=\frac{23}{45}\)
\(x=\frac{23}{45}:\frac{22}{45}\)
\(x=\frac{23}{22}\)
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right)x=\frac{23}{45}\)
\(\Rightarrow\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{8.9.10}\right).\frac{x}{2}=\frac{23}{45}\)
\(\Rightarrow\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)x=\frac{46}{45}\)
\(\Rightarrow\left(\frac{1}{1.2}-\frac{1}{9.10}\right)x=\frac{46}{45}\)
\(\Rightarrow\frac{22}{45}.x=\frac{46}{45}\Rightarrow x=\frac{46}{22}=\frac{23}{11}\)
