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\(D=\) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)
\(=\) \(\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\) \(\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(=\) \(\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(=\) \(\frac{3^{29}\left(11-3\right)}{3^{28}.4}\)
\(=\) \(\frac{3^{28}.3.8}{3^{28}.4}\)
\(=\) \(\frac{3^{28}.3.4.2}{3^{28}.4}\)
\(=\) \(6\)
Chúc bn hok tốt ~
\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)
\(=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)
\(=\frac{3^{29}\left(11-3\right)}{3^{28}.4}\)
\(=\frac{3^{28}.3.8}{3^{28}.4}\)
\(=\frac{3^{28}.3.4.2}{3^{28}.4}=6\)
Thế này à:
a, \(\frac{2^{13}+25}{2^{10}}\)
b, \(\frac{21^2.14.125}{35^5.6}\)
c,\(\frac{45^3.20^4.18^2}{180^5}\)
d, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
2 mũ 13 ta chia cho 2 mũ 10 ta có là 2 mũ 3 chuyển thành 8 rồi cộng cho 25 ta có là 33
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Ta có : \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)
\(\Rightarrow\) \(A=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.8}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow\) \(A=3.2\)
\(\Rightarrow\) \(A=6\)
Vậy A = 6
♥...♥...♥ Chúc bn họk tốt ♥...♥...♥