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* \(6x+3-2\left(x-5\right)=30\)
\(\Rightarrow6x+3-2x+10=30\)
\(\Rightarrow4x=17\Leftrightarrow x=\frac{17}{4}\)
* \(8\left(x-\frac{1}{8}\right)-5\left(x-\frac{1}{5}\right)=10\)
\(\Rightarrow3\left(x-\frac{1}{5}\right)=10\)
\(\Rightarrow x-\frac{1}{5}=\frac{10}{3}\)
\(\Rightarrow x=\frac{10}{3}+\frac{1}{5}=\frac{53}{15}\)
* \(13x-5-2\left(x+3\right)=1\)
\(\Rightarrow13x-5-2x-6=1\)
\(\Rightarrow11x=12\Leftrightarrow x=\frac{12}{11}\)
1) 14x-8x=10+5
x(14-8)=15
x6=15
x=15/6
2)5x-3x=30-15
2x=15
x=15/2
3)làm tương tự
1) 4x-(2x-5)=21
4x-2x+5=21
2x+5=21
2x=21 -5
2x=16
x=16/2
x=8
8)4(x-2)-2(x-1)=12
4x-8-(2x-2)=12
4x-8-2x+2=12
2x-8+2=12
2x=12-2+8
2x=18
x=18/2=9
9)6x-13-2-(x×5)=7
6x-5x=7+13+2
x=22
10)7(x-5)-3(x+5)=30
7x-35-(3x+15)=30
7x-35-3x-15=30
4x=30+35+15
4x=80
x=20
8)4(x-2)-2(x-1)=12
\(\Rightarrow4x-8-2x+2=12\)
\(\Rightarrow2x=18\)
\(=>x=9\)
9)6x-13-2-(x×5)=7
\(\Rightarrow6x-15-\left(x+5\right)=7\)
\(\Rightarrow6x-15-x-5=7\)
\(\Rightarrow5x=27\)
\(\Rightarrow x=\frac{27}{5}\)
10)7(x-5)-3(x+5)=30
\(\Rightarrow7x-35-3x-15=30\)
\(\Rightarrow4x=80\)
\(\Rightarrow x=20\)
1: Ta có: 7x+6(3-x)=27-20+73
\(\Leftrightarrow7x+18-6x=80\)
\(\Leftrightarrow x=80-18=62\)
Vậy: x=62
2: Ta có: \(6x-5\left(x-7\right)=\left(27-514\right)-486-73\)
\(\Leftrightarrow6x-5x+35=27-514-486-73\)
\(\Leftrightarrow x+35=-1046\)
\(\Leftrightarrow x=-1081\)
Vậy: x=-1081
1: =>|x-5|=5-7x+7x+28=33
=>x-5=33 hoặc x-5=-33
=>x=38 hoặc x=-28
3: 2|x-6|+7x-2=|x-6|+7x
=>|x-6|=2
=>x-6=2 hoặc x-6=-2
=>x=8 hoặc x=4
Giải:
a) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(x=\dfrac{-13}{12}\)
b) \(2.\left(x-\dfrac{1}{3}\right)=\left(\dfrac{1}{3}\right)^2+\dfrac{5}{9}\)
\(2.\left(x-\dfrac{1}{3}\right)=\dfrac{1}{9}+\dfrac{5}{9}\)
\(2.\left(x-\dfrac{1}{3}\right)=\dfrac{2}{3}\)
\(x-\dfrac{1}{3}=\dfrac{2}{3}:2\)
\(x-\dfrac{1}{3}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}+\dfrac{1}{3}\)
\(x=\dfrac{2}{3}\)
c) \(\left|2x-\dfrac{3}{4}\right|-\dfrac{3}{8}=\dfrac{1}{8}\)
\(\left|2x-\dfrac{3}{4}\right|=\dfrac{1}{8}+\dfrac{3}{8}\)
\(\left|2x-\dfrac{3}{4}\right|=\dfrac{1}{2}\)
\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{3}{4}=\dfrac{1}{2}\\2x-\dfrac{3}{4}=\dfrac{-1}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{8}\\x=\dfrac{1}{8}\end{matrix}\right.\)
d) \(\dfrac{2}{3}x+\dfrac{1}{6}x=3\dfrac{5}{8}\)
\(x.\left(\dfrac{2}{3}+\dfrac{1}{6}\right)=\dfrac{29}{8}\)
\(x.\dfrac{5}{6}=\dfrac{29}{8}\)
\(x=\dfrac{29}{8}:\dfrac{5}{6}\)
\(x=\dfrac{87}{20}\)
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