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\(\frac{1}{40}\)x\(\frac{1}{30}\)x\(\frac{1}{20}\)x\(\frac{1}{12}\)x\(\frac{1}{6}\)x\(\frac{1}{2}\)
= \(\frac{1}{40.30.20.12.6.2}\)
= \(\frac{1}{3456000}\)
k mik nha! (kb nhé!!!)
20x{90-[30-(2x3)2]}
=20x{90-[30-62]}
=20x{90-[30-36]}
=20x{90-(-6)}
=20x96
=1 920
Gọi biểu thức đó là A
\(A=\dfrac{1}{x}.\left(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+..+\dfrac{1}{49.50}\right)=1\)
\(\Rightarrow A=\dfrac{1}{x}.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{49.50}\right)=1\)
Ta có công thức : \(\dfrac{a}{b.c}=\dfrac{a}{c-b}.\left(\dfrac{1}{b}-\dfrac{1}{c}\right)\)
Dựa vào công thức trên ta có :
\(\dfrac{1}{2.3}=\dfrac{1}{2}-\dfrac{1}{3}\)
\(\dfrac{1}{3.4}=\dfrac{1}{3}-\dfrac{1}{4}\)
......................
\(\dfrac{1}{49.50}=\dfrac{1}{49}-\dfrac{1}{50}\)
\(\Rightarrow A=\dfrac{1}{x}.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+.....+\dfrac{1}{49}-\dfrac{1}{50}\right)=1\)
\(\Rightarrow A=\dfrac{1}{x}.\left(\dfrac{1}{2}-\dfrac{1}{50}\right)=1\)
\(\Leftrightarrow A=\dfrac{1}{x}.\left(\dfrac{12}{25}\right)=1\)
\(\Rightarrow\) \(\dfrac{1}{x}=A:\dfrac{12}{25}=1:\dfrac{12}{25}=\dfrac{25}{12}\)
Vậy x = 12.
Mink nghĩ vậy, ai thấy đúng thì ủng hộ mink nha !!!
2x-2016=2018
2x =2018+2016
2x =4034
x =4034:2
x =2017
3x +1=82
3x =82-1
3x =81
3x =34
x =4
20x-11=20x+2x-12
20x-11=x(20+2)-12
20x-11=22x-12
20x =22x-12+11
20x =22x-1
22x-2x=22x-1
2x =1
x =1:2
x =0,5
(x+1)+(x+2)+(x+3)+(x+4)=26
x+x+x+x+1+2+3+4 =26
4x+10 =26
4x =26-10
4x =16
x =16:4
x =4
\(20x+11⋮5x+1\)
\(20x+4+7⋮5x+1\)
\(4\left(5x+1\right)+7⋮5x+1\)
\(\Rightarrow7⋮5x+1\Rightarrow5x+1\inƯ\left(7\right)\)
\(Ư\left(7\right)=\left\{\pm1;\pm7\right\}\)
\(x\in\left\{0\right\}\)
\(\left(2x+1\right)+\left(4x+2\right)+....+\left(20x+10\right)=275\)
\(\Rightarrow\left(2x+4x+....+20x\right)+\left(1+2+3+....+10\right)=275\)
\(\Rightarrow110x+55=275\)
\(\Rightarrow110x=275-55\)
\(\Rightarrow110x=220\)
\(\Rightarrow x=2\)
(2x + 1) + (4x + 2) + (6x + 3) + ... + (20x + 10) = 275
(1 + 2 + 3 + ... + 10).(2x + 1) = 275
(1 + 10).10:2.(2x + 1) = 275
11.5.(2x + 1) = 275
55.(2x + 1) = 275
2x + 1 = 275 : 55
2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2
x = 2
Vậy x = 2
\(\frac{1}{20}\cdot\frac{1}{30}\cdot\frac{1}{42}\cdot\frac{1}{56}\cdot\frac{1}{72}\cdot\frac{1}{90}\)
\(=\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)
\(=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{4}-\frac{1}{10}\)
\(=\frac{6}{40}=\frac{3}{20}\)