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Bài 1:
a) [ (1/6 + 1/10 + 1/15) : (1/6 + 1/10 - 1/15) phần 1/2 - 1/3 + 1/4 - 1/5 ] : (1/4 - 1/6)
= [ (1/6 : 1/6) + (1/10 : 1/10) - (1/15 : 1/15) phần 30/60 - 20/60 + 15/60 - 12/60 ] : (3/12 - 2/12)
= [ 1 + 1 - 1 phần 13/60 ] : 1/12
= [ 1 : 13/60 ] x 12
= 60/13 x 12
=720/ 13
b) (3/20 + 1/2 - 1/15) x 12/49 phần 3 và 1/3 + 2/9
= (9/60 + 30/60 - 4/60) x 12/49 phần 10/3 + 2/9
= 7/12 x 12/49 phần 30/9 + 2/9
= 1/7 : 32/9
= 1/7 x 9/32
= 9/224
\(\dfrac{15}{8}:\dfrac{45}{6}-\dfrac{1}{13}\left(\dfrac{4}{9}-\dfrac{1}{12}\right)\)
\(=\dfrac{15}{8}\cdot\dfrac{6}{45}-\dfrac{1}{13}\left(\dfrac{48-9}{108}\right)\)
\(=\dfrac{1}{4}-\dfrac{1}{13}\cdot\dfrac{13}{36}\)
\(=\dfrac{1}{4}-\dfrac{1}{36}=\dfrac{2}{9}\)
\(\left(\frac{9}{10}+\frac{1}{10}\div\frac{4}{5}\right)\times\left(\frac{3}{15}-\frac{2}{15}\times\frac{4}{3}\times\frac{9}{8}\right)\)
\(=\left(1\div\frac{4}{5}\right)\times\left(\frac{3}{15}-\frac{1}{5}\right)\)
\(=\frac{5}{4}\times0\)
\(=0\)
\(\frac{12}{5}+\frac{1}{5}\times6-\frac{3}{4}\)
\(=2,4+0,2\times6-0,75\)
\(=2,4+1,2-0,75\)
\(=3,6-0,75=2,85\)
\(\frac{9}{7}-\frac{1}{7}\times3+\frac{15}{14}\)
\(=\frac{9}{7}-\frac{3}{7}+\frac{15}{14}\)
\(=\frac{18}{14}-\frac{6}{14}+\frac{15}{14}\)
\(=\frac{12}{14}+\frac{15}{14}\)
\(=\frac{27}{14}\)
1 x 3 x 5 + 2 x 6 x 10 + 3 x 9 x 15/3 x 5 x 12 + 6 x 10 x 24 + 9 x 15 x 36 = 15 + 120 + 8100 + 1440 + 4860 = 14535
\(\frac{1\times3\times5+2\times6\times10+3\times9\times15}{3\times5\times12+6\times10\times24+9\times15\times36}\)
\(=\frac{1\times3\times5\times\left(1+2^3+3^3\right)}{3\times5\times12\times\left(1+2^3+3^3\right)}\)\(=\frac{1}{12}\)
