64 : 0,5 + 64 : 0,25 + 64 x 4
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\(8,64\times93+8,64:0,5+8,64:0,25+8,64\)
\(=8,64\times93+8,64\times2+8,64\times4+8,64\times1\)
\(=8,64\times\left(92+4+2+1\right)\)
\(=8,64\times100\)
\(=864\)
a) 92 : 0,01 = 9200 92 x 100 = 9200 64 : 0,01= 6400
b) 25 : 0,5 = 50 25 x 2 = 50 39 : 0,5 = 78
c) 32 : 0,25 = 128 32 x 4 = 128 15 : 0,25 = 60
\(\left(0,75\times64-32\times2\times\frac{3}{4}\right):\left(0,25\times19\times2\times2017\right)\)
= \(\left[64\times\left(0,75-\frac{3}{4}\right)\right]:\left(0,25\times19\times2\times2017\right)\)
= \(\left(64\times0\right):\left(0,25\times19\times2\times2017\right)\)
= \(0:\left(0,25\times19\times2\times2017\right)\)
= \(0\)
\(\left[\left(0,5\right)^3\right]^x=\dfrac{1}{64}\\ \Leftrightarrow\left[\left(\dfrac{1}{2}\right)^3\right]^x=\dfrac{1}{64}\\ \Leftrightarrow\left(\dfrac{1}{8}\right)^x=\dfrac{1}{64}=\left(\dfrac{1}{8}\right)^2\\ Vậy:x=2\\ \rightarrow S=\left\{2\right\}\)
Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)
\(\Leftrightarrow3x=6\)
hay x=2
\(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Rightarrow\left(-\dfrac{1}{8}\right)^x=\left(-\dfrac{1}{8}\right)^2\)
\(\Rightarrow x=2\)
Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)
\(\Leftrightarrow3x=6\)
hay x=2
\(y\text{×}5+y:0,25=81\)
\(y\text{×}5+y\text{×}4=81\)
\(y\text{×}\left(5+4\right)=81\)
\(y\text{×}9=81\)
\(y=81:9\)
\(y=9\)
\(y\text{×}3+y:0,2=64\)
\(y\text{×}3+y\text{×}5=64\)
\(y\text{×}\left(3+5\right)=64\)
\(y\text{×}8=64\)
\(y=64:8\)
\(y=8\)
64:0,5 + 64:0,25 + 64\(\times4\)
= 64 \(\times\) 2 + 64 \(\times\) 4 + 64 \(\times\) 4
= 64 \(\times\) ( 2 + 4 + 4)
= 64 \(\times\) 10
= 640