Tính bằng cách thuận tiện nhất:
69,78 + 35,97 x 3,2 : 1,5
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69,78 + 35,97 + 30,22 = (69,78 + 30,22) + 35,97=100 + 35,97=135,97
a)69,78 + 35,97 + 30,22
=(69,78+30,22)+35,97
=100 + 35,97
=135,97
b)83,45 - 30,98 - 42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{72-28-14}{99}\)\(=\frac{30}{99}=\frac{10}{33}\)
\(\left(69,78+30,22\right)+35,97\)\(=100+35,97=135,97\)
\(83,45-\left(30,98+42,47\right)\)\(=83,45-73,45=10\)
72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99-42/99
=30/99=10/33
67,78+35,97+30,22
=(67,78+30,22)+35,97
=98+35,97
=133,97
83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
a) 7/11+3/4+4/11+1/4
=(7/11+4/11)+(3/4+1/4)
= 1 + 1
= 2.
b) 72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99- 42/99
= 30/99=10/33.
c) 69,78+35,97+30,22
=(69,78+30,22)+35,97
= 100 +35,97
= 135,97.
d) 83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45- 73,45
= 10.
a) \(\dfrac{7}{11}+\dfrac{3}{4}+\dfrac{4}{11}+\dfrac{1}{4}=\left(\dfrac{7}{11}+\dfrac{4}{11}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=1+1=2\)
b) \(\dfrac{72}{99}-\dfrac{28}{99}-\dfrac{14}{99}=\dfrac{72-28-14}{99}=\dfrac{30}{99}=\dfrac{10}{33}\)
\(a,=69,78\times\left(\dfrac{3}{4}+\dfrac{1}{4}+99\right)\\ =69,78\times\left(\dfrac{4}{4}+99\right)\\ =69,78\times\left(1+99\right)=69,78\times100=6978\\ b,34,1\times8+34,1\times0,5\\ =34,1\times\left(8+0,5\right)\\ =34,1\times8,5\\ =289,85\)
a: =69,78(3/4+1/4+99)
=69,78*100
=6978
b: =34,1(8+0,5)=34,1*8,5=289,85
69,78+35,97x3,2:1,5
=1x\(\left(69,78+35,97\right)\)x3,2:1,5
=1x105,75x3,2:1,5
=317,25:1,5
=211,5